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Bumek [7]
3 years ago
15

Y squared plus 7y plus 10 over y squared minus 25

Mathematics
1 answer:
klasskru [66]3 years ago
5 0
Y²+7y+10/y²-25 this is the equation now if your looking for the answer it would be

y^4+7y^3-25y^2-175y+10
_________________________
(y+5)(y-5)

sorry if is a little messy
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damaskus [11]
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3 0
3 years ago
Read 2 more answers
Estimate the perimeter and the area of the shaded figure to the nearest tenth.<br> -Please help me-
Crank

Answer:

Perimeter = 12+4pi

Area = 16+8pi

Step-by-step explanation:

Description of the assumed shape:

A rectangle 2 x 8 superimposed on a semi-circle of radius 4.

Perimeter:

P = 2+8+2+(4)(pi) = 12+4pi

Area :

A = 2*8 +(pi)4^2/2 = 16 + 8pi

3 0
3 years ago
3. Consider the linear equation 2y - 3x = 5.
nignag [31]

Answer:

Step-by-step explanation:

a.

2y - 3x = 5

2(-2) - 3x = 5

-4 - 3x = 5

-3x = 9

x = -3

(-3,-2) is another solution

b.

(-1,1)

2y - 3x = 5

2(1) - 3(-1) = 5

2 + 3 = 5

5 = 5

true, the point is a solution to the equation because the equation is true after substituting x and y with the point (-1,1)

(4,1)

2y - 3x = 5

2(1) - 3(4) = 5

2 - 12 = 5

-10 = 5

not true, the point is not a solution to the equation because the equation is not true after substituting x and y with the point (4,1)

c. You can use the points from the given (-1,1) and (-3,-2) to form a line. You then shade whichever half solves the solution using points on the graph.

8 0
2 years ago
Find the area of each figure
jeka94

Answer:

50.74 yds^2

Step-by-step explanation:

7 0
3 years ago
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