This is a case of both Rh incompatibility and ABO incompatibility. Since the first pregnancy is normal but the second one resulted in hemolytic disease; it means that in the first pregnancy, the baby was Rh negative which lead the Rh positive mother to produce antibodies against Rh negative blood, which is noted in the second pregnancy leading to hemolytic disease. There may also be a form of ABO incompatibility. The correct answer is that both of her children are type A, Rh negative, and the mother is a type B, Rh positive.
The answer is A I hope this works
Answer:
A zygote is a fertilized ovum. The germ cells undergo meiosis to reach a haploid state (n) as part of spermatogenesis and oogenesis. The sperm and the unfertilized ovum reinstates a chromosome set in zygote in a diploid state (2n).
After fusing with the sperm, the second stage of meiosis takes place for separation of chromatids. Post-fertilization, mitosis of the zygote is initiated which develops into a mature offspring exhibiting characteristics of its parent.
Explanation:
The zygote stage development occurs in the first week of fertilization. The genome of the zygote is the combination of DNA in each gamete and contains all the genetic information required to form an individual.
Carbondraytes (sorry if spelled wrong)
