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Ivenika [448]
3 years ago
7

Two quantities, x and y, are directly proportional. If x is tripled, what happens to y? It is multiplied by 13. It is tripled. I

t is multiplied by 9. It depends on the starting value of x.
Mathematics
2 answers:
prisoha [69]3 years ago
7 0
Answer: It is tripled.

Since x and y are proportional, whatever happens to x must happen to y in order for the two values to stay proportional.
viktelen [127]3 years ago
3 0

Answer:

Option B.

Step-by-step explanation:

It is given that two quantities, x and y, are directly proportional. It means

y\propto x

y=kx

where, k is constant of proportionality.

We need to find the effect on y if x is tripled.

Let x_1=3x, then

y_1=k(3x)

y_1=3(kx)

y_1=3y

It means y is also tripled.

Therefore, the correct option is B.

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250 \times 12 = 3000
40 \times 12 = 480
54000 + 3000 + 480 = 57480
the answer is C
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3 years ago
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What is the y-intercept of this graph?
melisa1 [442]

Answer:

The Y-intercept is 0.

Step-by-step explanation:

5 0
3 years ago
The plane x + y + z = 12 intersects paraboloid z = x^2 + y^2 in an ellipse.(a) Find the highest and the lowest points on the ell
emmasim [6.3K]

Answer:

a)

Highest (-3,-3)

Lowest (2,2)

b)

Farthest (-3,-3)

Closest (2,2)

Step-by-step explanation:

To solve this problem we will be using Lagrange multipliers.

a)

Let us find out first the restriction, which is the projection of the intersection on the XY-plane.

From x+y+z=12 we get z=12-x-y and replace this in the equation of the paraboloid:

\bf 12-x-y=x^2+y^2\Rightarrow x^2+y^2+x+y=12

completing the squares:

\bf x^2+y^2+x+y=12\Rightarrow (x+1/2)^2-1/4+(y+1/2)^2-1/4=12\Rightarrow\\\\\Rightarrow (x+1/2)^2+(y+1/2)^2=12+1/2\Rightarrow (x+1/2)^2+(y+1/2)^2=25/2

and we want the maximum and minimum of the paraboloid when (x,y) varies on the circumference we just found. That is, we want the maximum and minimum of  

\bf f(x,y)=x^2+y^2

subject to the constraint

\bf g(x,y)=(x+1/2)^2+(y+1/2)^2-25/2=0

Now we have

\bf \nabla f=(\displaystyle\frac{\partial f}{\partial x},\displaystyle\frac{\partial f}{\partial y})=(2x,2y)\\\\\nabla g=(\displaystyle\frac{\partial g}{\partial x},\displaystyle\frac{\partial g}{\partial y})=(2x+1,2y+1)

Let \bf \lambda be the Lagrange multiplier.

The maximum and minimum must occur at points where

\bf \nabla f=\lambda\nabla g

that is,

\bf (2x,2y)=\lambda(2x+1,2y+1)\Rightarrow 2x=\lambda (2x+1)\;,2y=\lambda (2y+1)

we can assume (x,y)≠ (-1/2, -1/2) since that point is not in the restriction, so

\bf \lambda=\displaystyle\frac{2x}{(2x+1)} \;,\lambda=\displaystyle\frac{2y}{(2y+1)}\Rightarrow \displaystyle\frac{2x}{(2x+1)}=\displaystyle\frac{2y}{(2y+1)}\Rightarrow\\\\\Rightarrow 2x(2y+1)=2y(2x+1)\Rightarrow 4xy+2x=4xy+2y\Rightarrow\\\\\Rightarrow x=y

Replacing in the constraint

\bf (x+1/2)^2+(x+1/2)^2-25/2=0\Rightarrow (x+1/2)^2=25/4\Rightarrow\\\\\Rightarrow |x+1/2|=5/2

from this we get

<em>x=-1/2 + 5/2 = 2 or x = -1/2 - 5/2 = -3 </em>

<em> </em>

and the candidates for maximum and minimum are (2,2) and (-3,-3).

Replacing these values in f, we see that

f(-3,-3) = 9+9 = 18 is the maximum and

f(2,2) = 4+4 = 8 is the minimum

b)

Since the square of the distance from any given point (x,y) on the paraboloid to (0,0) is f(x,y) itself, the maximum and minimum of the distance are reached at the points we just found.

We have then,

(-3,-3) is the farthest from the origin

(2,2) is the closest to the origin.

3 0
3 years ago
Solve each equation by completing the square NEED THIS IN 10 MINS WILL GIVE BRAINLIEST
yulyashka [42]

Answer:

Step-by-step explanation:

7(b² - 2b - 8) = 0

7(b² - 2b +   ) = 8

7(b² - 2b + 1) = 8 + 1

7(b - 1)² = 9

(b - 1)² = 9/7

b - 1 = ±√(9/7)

b = 1 ±3√(1/7)

b ≈ -0.134, 2.134

m² + 10m + 14  = -7

m² + 10m +      = -7 - 14

m² + 10m + 25 = -7 - 14 + 25

(m + 5)² = 4

m + 5 = 2

m = -3

p² - 8p + 21 = 6

p² - 8p +     = 6 -21

p² - 8p + 16 = 6 -21 + 16

(p - 4)² = 1

p - 4 = 1

p = 5

4 0
3 years ago
suppose linda had 2/3 of a yard of fabric and told Sandra that she used 3/4 of a yard. Sandra says this is not possible. Do you
zepelin [54]
I do not agree because 3/4 is greater than 2/3 so you can not do 3/4-2/3
7 0
3 years ago
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