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3 years ago

10

PLEASE URGENT HELP!!!

1 answer:

olchik [2.2K]3 years ago

3 0

Answer:

The equation is;

y = 1/3x

Step-by-step explanation:

The equation of a linear model is given as;

y = mx + b

m is the slope while b is the y intercept

As we can see, the y intercept is the origin and that means b is zero

To get the value of m, the slope, we have to use the slope equation

We simply select any two points on the line

We have the points as (6,2) and (15,5)

The equation of the slope is:

m = (y2-y1)/(x2-x1)

(x1,y1) = (6,2)

(x2,y2) = (15,5)

m = (5-2)/(15-6) = 3/9 = 1/3

So the equation will be;

y = 1/3x

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Distribute<br>(x-4)(x+2)<br><br>a) x^2+6x-8<br>b) x^2-2x-8<br>c) x62-6x-8<br>d) x^2+2x-8

user100 [1]

The answer: B. x^2-2x-8

6 0

3 years ago

Evaluate the integral Integral from (5 comma 2 comma 4 )to (7 comma 9 comma negative 3 )y dx plus x dy plus 3 dz by finding para

padilas [110]

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_{(5,2,4)}^{(7,9,-3)}y\,\mathrm dx+x\,\mathrm dy+3\,\mathrm dz$

Parameterize the line segment (call it $C$ ) by

$\vec r(t)=(1-t)(5\,\vec\imath+2\,\vec\jmath+4\,\vec k)+t(7\,\vec\imath+9\,\vec\jmath-3\,\vec k)$

$\vec r(t)=(2t+5)\,\vec\imath+(7t+2)\,\vec\jmath+(4-7t)\,\vec k$

with $0\le t\le1$ . Then

$\vec r'(t)=2\,\vec\imath+7\,\vec\jmath-7\,\vec k$

and the line integral is

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^1((7t+2)\,\vec\imath+(2t+5)\,\vec\jmath+3\,\vec k)\cdot\vec r'(t)\,\mathrm dt$

$=\displaystyle\int_0^1((2t+5)+2(7t+2)-21)\,\mathrm dt$

$=\displaystyle\int_0^1(28t+18)\,\mathrm dt=\boxed{32}$

Alternatively, if we can show that $\vec F$ is conservative, then we can apply the fundamental theorem of calculus. We need to find $f$ such that $\nabla f=\vec F$ , which requires

$\dfrac{\partial f}{\partial x}=y$

$\dfrac{\partial f}{\partial y}=x$

$\dfrac{\partial f}{\partial z}=3$

Integrating both sides of the first equation with respect to $x$ gives

$f(x,y,z)=xy+g(y,z)$

Differentiating both sides wrt $y$ gives

$\dfrac{\partial f}{\partial y}=x=x+\dfrac{\partial g}{\partial y}$

$\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

Differentiating wrt $z$ gives

$\dfrac{\partial f}{\partial z}=3=\dfrac{\mathrm dh}{\mathrm dz}$

$\implies h(z)=3z+C$

So we have

$f(x,y,z)=xy+3z+C$

and $\vec F$ is conservative. By the FTC, we find

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=f(7,9,-3)-f(5,2,4)=\boxed{32}$

5 0

3 years ago

NEED HELP ASAP!!!!

timama [110]

Answer:

i think its 3x-8 not sure

8 0

3 years ago

In the given figure find the value of x.

jek_recluse [69]

Answer:

It needs to equal 180 so just do that

5 0

3 years ago

if the measurements of a quadrilateral is 68 degrees and52 degrees and 125 degrees what is the missing angle

alex41 [277]

Answer:

Step-by-step explanation:

Quadrilaterals add up to 360 degrees.

Let the missing angle = x

68 + 52 + 125 + x = 360

245 + x = 360

Subtract 245 from both sides.

245 - 245 + x = 360 - 245

Combine

x = 115

4 0

3 years ago