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leonid [27]
3 years ago
10

A rectangle is drawn on a coordinate plane. Three vertices of the rectangle are points A(−4,3) , B(2,3) , and C(2,−1) . Point D

is the fourth vertex of the rectangle. What is the distance from point C to point D?
Mathematics
2 answers:
Dovator [93]3 years ago
7 0

Answer:

Distance CD = 6

Step-by-step explanation:

In a rectangle ABCD coordinates of A(-4, 3), B(2, 3) and C(2, -1) are given.

We have to find the distance between points C and D when D is the fourth vertex of the rectangle.

Since in a rectangle length of opposite sides are equal, so AB = CD

distance between A(-4, 3) and B(2,3) = distance between points C and D

√(2+4)²+ (3-3)² = CD

CD = √6² = 6

Therefore CD = 6 is the answer.

Varvara68 [4.7K]3 years ago
3 0
Coordinates of D= (-4,-1)

=> distance from point C to point D is 6 units
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First to see how Much Norm used, we need to subtract 373 from 500 (500-373) and you get 127. To express this as a fraction you put 127 over 500. then the decimal would be 127 divided into 500. Which is .254 . The answer in fraction form is 127/500 and in decimal is .254
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4 years ago
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Rectangle JKLM with vertices J(-3,2), K(3,5), L(4,3), M(-2,0)<br> translation please
Wewaii [24]

Answer:

NOT! (10, 1)

Step-by-step explanation:

3 0
3 years ago
Kendall measured the temperature outside to be 68°F. She needs to convert the temperature to degrees celsius.
Vanyuwa [196]

Answer:

68°F is 20°C

Step-by-step explanation:

C = (5/9)(F - 32)

C = (5/9)(68 - 32)

C = (5/9)(36)

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C = 20

Answer: 68°F is 20°C

5 0
4 years ago
From a ship, the angle of elevation of a point, A, at the top of a cliff is 21°. After the ship has sailed 2,500 feet directly t
fredd [130]

Answer:

10701.97 feet.

Step-by-step explanation:

Refer the attached figure

The angle of elevation of a point, A, at the top of a cliff is 21° i.e. ∠ACB = 21°

The ship has sailed 2,500 feet directly toward the foot of the cliff i.e. CD = 2500 feet.

Then the angle of elevation becomes 47° i.e.∠ADB = 47°

Let BD be x

So, BC = BD+DC=x+2500

Let the height of the cliff be h feet.

In ΔABD

We will use trigonometric ratios

tan\theta = \frac{Perpendicular}{Base}

tan47^{\circ} = \frac{AB}{BD}

1.072= \frac{h}{x}

1.072x=h    ---a

In ΔABC

We will use trigonometric ratios

tan\theta = \frac{Perpendicular}{Base}

tan21^{\circ} = \frac{AB}{BC}

0.869 = \frac{h}{x+2500}

0.869(x+2500) =h

0.869x+2172.5 =h   -----b

Equate a and b

0.869x+2172.5 =1.072x

2172.5 =1.072x-0.869x

2172.5 =0.203x

\frac{2172.5}{0.203}=x

10701.97=x

Thus the height of the cliff is 10701.97 feet.

4 0
3 years ago
How does the value of b affect the graph of the equation?
slamgirl [31]
Hey there!
B in a slope intercept form equation is the the y intercept. It dictates where the line will cross the y axis, and therefore the line's placement altogether. This is because if there was no y intercept, the line would only be shaped by the slope, and would start at 0.
Hope this helped!
4 0
4 years ago
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