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Ksenya-84 [330]
3 years ago
14

rounded to the nearest whole, what is the radius length if minor arcYZ = 12 and angleYXZ is one-third of a full circle? (i guess

ed it idk if it’s right)

Mathematics
1 answer:
Oksanka [162]3 years ago
4 0

Answer:

Option (1)

Step-by-step explanation:

Since the length of arc YZ = 12 units

m∠YXZ = one third of the full circle = \frac{360}{3} = 120°

From the formula of arc length,

Length of arc = \frac{\theta}{360}(2\pi r)

Where θ = Central angle subtended by the arc

r = radius of the circle

By substituting these values in the formula,

12 = \frac{120}{360}(2\pi r)

12 = \frac{2}{3}\pi r

18=\pi r

r = \frac{18}{\pi }

r = 5.73

r ≈ 6 units

Therefore, Option (1) will be the answer.

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4 years ago
A 15​-ft by 15​-ft rectangular swimming pool is surrounded by a walkway of uniform width. If the total area of the walkway is 13
andrezito [222]

Answer:

2ft wide

Step-by-step explanation:

Total Area = Area of the summing pool +  total Area of the walkway.

Area of the summing pool = 15 × 15 = 225ft²

And total area of walkway = 136ft²

∴ total area = 225 + 136 = 361 ft².

Let w = The width of the walkway.

Since the walkway has a uniform width

∴ Total Area of pool and walkway = (15+2w)(15+2w)

⇒ (15+2w)(15+2w) = 361........................(1)

 Expanding Equation(1)

 15×15 + 15×2w + 2w×15 + 2w×2w = 361

 ⇒ 225 + 30w + 30w + 4w² = 361................(2)

  Rearranging equation(2) above and collecting like terms

   4w²+60w = 361-225

    4w² + 60w = 136..............................(3)

   Dividing all through equation(3) by 4

   4w²/4 + 60w/4 = 136/4

    w² + 15w = 34..............(4)

    rearranging equation(4)

    w²+15w -34 = 0

Using factorization method to solve the quadratic equation,

   w² + 15w - 34 = 0

Two numbers whose sum give +15 and whose product gives -34

are +17 and -2.

∴ w² -2w +17w -34 =0

   grouping the equation,

   (w²-2w) + (17w-34) =0

  Bringing out the common terms in both bracket.

  w(w-2) +17(w-2) =0

 since both term in the bracket are the same, take one of the term in the bracket and form a bracket for the outer term i.e

(w-2)(w+17)=0.

Either w-2 =0

           w=+2

OR    w+17 =0

          w=-17.

The right answer is w=+2 as wide can not be negative.

∴ The walkway is 2ft wide.

 

 

4 0
3 years ago
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