All categories

3 years ago

What is a number that can evenly be divided by 70 and 65

Mathematics

1 answer:

Tasya [4]3 years ago

4 0

4,550 is the answer when you multiply the two numbers together.

You might be interested in

Which quiz did met have a better score?

MaRussiya [10]

I'm her first quiz she did better, this is going to be hard to explain but pay attention 92% as a decimal is 92/100 keep this in mind, then 27 out of 30 question we try to make 30 go into 100 but we know 30 can't go into 100 without a decimal so what we do is we change the decimal to 90 so for the 27 out of 30 it is now 81/90, now we need to change the denominator in 92/100 to 90 so we subtract 10 from the numerator and denominator to get 82/100 so compare the 2 decimals you got 81/90 and 82/90 and you find that 82/90 is bigger so she did better on the first quiz

7 0

3 years ago

Read 2 more answers

4b2 + 5b - 27

joja [24]

Answer:

The answer is C, the coefficient.

7 0

3 years ago

A number that has a digit in tenths place, hundredths place or beyond

givi [52]

Decimal- A number that has a digit in the tenths place, hundredths place, and/ or beyond.

8 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST

a_sh-v [17]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If S is countable and nonempty, prove their exist a surjection g: N --> S

aleksley [76]

Answer with Step-by-step explanation:

We are given S be any set which is countable and nonempty.

We have to prove that their exist a surjection g:N $\rightarrow S$

Surjection: It is also called onto function .When cardinality of domain set is greater than or equal to cardinality of range set then the function is onto

Cardinality of natural numbers set = $\chi_0$ ( Aleph naught)

There are two cases

1.S is finite nonempty set

2.S is countably infinite set

1.When S is finite set and nonempty set

Then cardinality of set S is any constant number which is less than the cardinality of set of natura number

Therefore, their exist a surjection from N to S.

2.When S is countably infinite set and cardinality with aleph naught

Then cardinality of set S is equal to cardinality of set of natural .Therefore, their exist a surjection from N to S.

Hence, proved

8 0

3 years ago