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2 years ago

12

Find the domain and range of the following absolute value functions. fx)=|x-1|+2 I’ll mark brainliest to whoever answers first

1 answer:

andrew-mc [135]2 years ago

7 0

Answer:

Domain is All Real x.

Range is f(x) ≥ 2.

Step-by-step explanation:

The vertical lines about the x - 1 means the Absolute value ( always positive).

|x - 1| will always be positive or 0 and it's graph is shaped like a V with the vertex at (1, 0)

The + 2 will move the graph up 2 units so the vertex becomes (1, 2).

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Timmy wants to buy a scooter and the price was $50. When

Lunna [17]

Answer:

$30

Srry if its wrong

Step-by-step explanation:

3 0

2 years ago

Find the Circumference of a circle with a Diameter of 9 inches Group of answer choices 9 pi inches 9 pi inches^2 9 pi inches^3 1

katen-ka-za [31]

Answer: $9\pi\ in.$

Step-by-step explanation:

Given

The diameter of a circle is $d=9\ in.$

So, the radius is $r=\frac{d}{2}=4.5\ in.$

The circumference is given by $2\pi r$

Insert the values

$\Rightarrow 2\pi \cdot 4.5\\\Rightarrow 9\pi \ in.$

Thus, the circumference of the circle is $9\pi\ in.$

8 0

2 years ago

A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.

noname [10]

Answer:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

Step-by-step explanation:

Given

$Volume = 128ft^3$

$L = 2W$

$Base\ Cost = \$9/ft^2$

$Sides\ Cost = \$6/ft^2$

Required

The dimension that minimizes the cost

The volume is:

$Volume = LWH$

This gives:

$128 = LWH$

Substitute $L = 2W$

$128 = 2W * WH$

$128 = 2W^2H$

Make H the subject

$H = \frac{128}{2W^2}$

$H = \frac{64}{W^2}$

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

$A = LW + 2(WH + LH)$

The cost is:

$Cost = 9 * LW + 6 * 2(WH + LH)$

$Cost = 9 * LW + 12(WH + LH)$

$Cost = 9 * LW + 12H(W + L)$

Substitute: $H = \frac{64}{W^2}$ and $L = 2W$

$Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)$

$Cost =18W^2 + \frac{768}{W^2}*3W$

$Cost =18W^2 + \frac{2304}{W}$

To minimize the cost, we differentiate

$C' =2*18W + -1 * 2304W^{-2}$

Then set to 0

$2*18W + -1 * 2304W^{-2} =0$

$36W - 2304W^{-2} =0$

Rewrite as:

$36W = 2304W^{-2}$

Divide both sides by W

$36 = 2304W^{-3}$

Rewrite as:

$36 = \frac{2304}{W^3}$

Solve for $W^3$

$W^3 = \frac{2304}{36}$

$W^3 = 64$

Take cube roots

$W = 4$

Recall that:

$L = 2W$

$L = 2 * 4$

$L = 8$

$H = \frac{64}{W^2}$

$H = \frac{64}{4^2}$

$H = \frac{64}{16}$

$H = 4$

Hence, the dimension that minimizes the cost is:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

8 0

2 years ago

I’m struggling on both of them can you give both answers

Leona [35]

4.16 hours and 4 cups

Step-by-step explanation:

10. To find the % of something simply turn 5/6 in to a decimal (.83) then times it by the number you want .83 * 60 = 50 so its about 50 min each class, just times it by 5 =250 and lastly divide it by 60 for hours <u>4.16</u>

11. Simply times it by 6, 2/3*6= <u>4</u><u> </u><u>c</u><u>u</u><u>p</u><u>s</u>

4 0

3 years ago

Read 2 more answers

For males in a certain town, the systolic blood pressure is normally distributed with a mean of 125 and a standard deviation of

makkiz [27]

95% have a systolic blood pressure between 109 and 141

Empirical rule states that for a normal distribution, 68% are within one standard deviation from the mean, 95% are within two standard deviation from the mean and 99.7% are within three standard deviation from the mean.

Given that mean (μ) = 125, standard deviation (σ) = 8.

68% are within one standard deviation = μ ± σ = 125 ± 8 = (117, 133)

95% are within two standard deviation = μ ± 2σ = 125 ± 2*8 = (109, 141)

95% have a systolic blood pressure between 109 and 141

Find out more on empirical rule at: brainly.com/question/10093236

5 0

2 years ago