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Fantom [35]
3 years ago
5

ann has 5 brand new CD’s, which is 3 less than twice the that bob (x) has. translate the situation into an algebraic equation

Mathematics
1 answer:
Nataliya [291]3 years ago
6 0

Ann = 3 CD's

Ann = 2x-3

5 = 2x-3

x= CD's bob has

5 = 2x-3 is the equation

to solve

add 3 to each side

8 = 2x

divide by 2

x =4

bob has 4 CD's, ann has 5

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Wrong answers will be reported ​
PIT_PIT [208]

The solution to the equation is p = 1/3 and q = undefined

<h3>How to solve the equation?</h3>

The equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

The best way to solve the above equation is by the use of a graphing calculator i.e. graphically

However, it can be solved algebraically too (to some extent)

Recall that the equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

Split the equation

So, we have

p^2 - 2qp + 1/q = 0

p - 1/3 = 0

Solve for p in p - 1/3 = 0

p = 1/3

Substitute p = 1/3  in p^2 - 2qp + 1/q = 0

So, we have

(1/3)^2 - 2q(1/3) + 1/q = 0

This gives

1/9 - 2/3q + 1/q = 0

This gives

2/3q + 1/q = -1/9

Multiply though by q

So, we have

2/3q^2 + 1 = -1/9q

Multiply through by 9

6q^2 + 9 = -q

So, we have

6q^2 + q + 9 = 0

Using the graphing calculator, we have

q = undefined

Hence. the solution to the equation is p = 1/3 and q = undefined

Read more about equations at:

brainly.com/question/13763238

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5 0
2 years ago
Jacob earned 300 on an amount deposited into his bank account for 3 years at a 2% annual simple interest rate how much did Joe d
vampirchik [111]
Joe deposited 180.

300 x .02 x 3 = 180
3 0
3 years ago
Describe 58 as a sum of tens and ones
Solnce55 [7]
58 is 5 tens (5*10) and 8 ones (8*1)
4 0
3 years ago
Drag each graph to show if the system of linear equations it represents will have no
zimovet [89]
That’s a good question. But I don’t know the answer
3 0
3 years ago
Please someone what is the total surface area of this pryamid ​
Dimas [21]

Answer:

\large\boxed{C.\ (25+25\sqrt3)\ in^2}

Step-by-step explanation:

We have the square and four equilateral triangles.

The formula of an area of a squre:

A_S=a^2

a - length of side

The formula of an area of an equilateral triangle:

A_T=\dfrac{a^2\sqrt3}{4}

a - length of side

Clculate the areas:

SQURE:

A_S=x^2\ in^2

TRIANGLE:

A_T=\dfrac{x^2\sqrt3}{4}\ in^2

The SURFACE AREA of a square pyramid:

S.A.=A_S+4A_T\\\\S.A.=x^2+4\cdot\dfrac{x^2\sqrt3}{4}=x^2+x^2\sqrt3

Put x = 5:

S.A.=5^2+5^2\sqrt3=(25+25\sqrt3)\ in^2

7 0
3 years ago
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