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2 years ago

Two thirds of a number reduced by 11 is equal to 4 more than the number. Find the number. n= Answer

Mathematics

2 answers:

Ira Lisetskai [31]2 years ago

8 0

Answer:

-45

Step-by-step explanation:

2/3x - 11 = x + 4

I created an inequality representing the above statement first. This makes things look less complicated than what the question is asking.

2/3x = x + 15

solve for x. I started by adding 11 to both sides.

-1/3x = 15

multiply both sides by -3

x = -45

Ilia_Sergeevich [38]2 years ago

4 0

Answer:

-45.

Step-by-step explanation:

2/3 x - 11 = x + 4

2/3 x - x = 4 + 11

-1/3x = 15

x = 15 * -3

x = -45.

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The value of the bike after a year becomes only 80% of the value a year ago. In this given, the initial amount $500 should be multiplied by 80% 5 times. The answer would be $163.84. Thus, after 5 years the dirt bike would only be $163.84.

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3 years ago

Read 2 more answers

A sum amount <br>to rupees 34476 in two and a half years at 4% CI. the sum is

Kruka [31]

Given:

Amount = Rs. 34476

Rate of compound interest = 4%

Time = $2\dfrac{1}{2}=2.5$ years

To find:

The principal value.

Solution:

Formula for amount is

$A=P\left(1+\dfrac{r}{100}\right)^t$

Where, P is principal value, r is rate of interest and t is time in years.

Putting the given values, we get

$34476=P\left(1+\dfrac{4}{100}\right)^{2.5}$

$34476=P\left(1+0.04\right)^{2.5}$

$34476=P\left(1.04\right)^{2.5}$

$\dfrac{34476}{\left(1.04\right)^{2.5}}=P$

Now,

$P=31256.0090$

$P\approx 31256$

Therefore, the value of sum or principal value is Rs.31256.

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2 years ago

Two mechanics work on a car . The first mechanic worked 10 hours and the second mechanic worked for 15 hours. Together they char

GarryVolchara [31]

Its because of the hours they spent

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3 years ago

What is the value of x

Effectus [21]

4x+2x=180
6x= 180
Divide by 6
X= 30

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2 years ago

Problem page a delivery truck is transporting boxes of two sizes: large and small. the large boxes weigh 45 pounds each, and the

marta [7]

S= number of small boxes
l= number of large boxes

equation 1: s+l=120
equation 2: 15s+45l=3300

solve by elimination, multiply equation 1 by -15.

-15(s+l=120) = -15s-15l=-1800 add to equation 2.

-15s+15s-15l+45l=-1800+3300 = 30l=1500

30l=1500 , l=50

s+l=120, s+50=120 --> s=70

7 0

3 years ago