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3 years ago

10

Brenda cuts a pie into several equal slices. She gives Sally 2 slices of the pie. Peter takes a quarter of the pie. Henry takes

5 slices, and Brenda is left with 2 slices. How many slices did Brenda cut the pie into? What fraction of the pie does Brenda have left?

1 answer:

Juli2301 [7.4K]3 years ago

6 0

Brenda cut the pie into 12 slices. Brenda has 2/12 of the pie or 1/6 of the pie left for herself.

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Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

<u>case b)</u> $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

<u>case c)</u> $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

<u>case d)</u> $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

$x^{2}-2x-4=0$

5 0

2 years ago

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A basket is filled with 7 white eggs and 14 brown eggs. Half of the brown eggs are cracked.

Margaret [11]

1/3 chance of getting a cracked egg

4 0

3 years ago

If you have drums that hold 60 gallons and you need to ship 5,300 liters of liquid, how many drums will you need?

stiks02 [169]

The answer is 88 1/3.

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3 years ago

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The sum of two numbers is 61. The larger number is 13 more than the smaller number. What are the numbers?

patriot [66]

Answer: 24 and 37

Step-by-step explanation:

Let the numbers be x and y . Also let us pick x as the larger number.

From the first statement :

x + y = 61 ............................ equation 1

From the second statement :

x = y + 13 ............................equation 2

Solving the resulting linear equations by substitution method, substitute x = y + 13 into equation 1, then

x + y = 61 becomes

y + 13 + y = 61

2y + 13 = 61

2y = 48

y = 24

Substitute y = 24 into equation 2 , then

x = y + 3 becomes

x = 24 + 13

x = 37

Therefore the numbers are 24 and 37

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3 years ago

Find the trig ratio. Reduce to<br> lowest terms.<br> 6<br> А<br> 8<br> [?]<br> sin A<br> US

Maslowich

Answer:

3/5 will be the reduced answer

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2 years ago

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