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3 years ago

The base of a square fountain has an area of 144 ft2. What length of fence is needed to create a border for the fountain?

Mathematics

2 answers:

levacccp [35]3 years ago

5 0

Answer:

48 edge 2020

Step-by-step explanation:

PtichkaEL [24]3 years ago

3 0

Answer:

Step-by-step explanation:

Area of a square = length of side squared

square root of 144 is 12

four equal sides in a square

12 * 4 = 48

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the builder measures the perimeter of the foundation to be 425 ft. he must order steel beams to install around the perimeter of

Ad libitum [116K]

Answer:

The builder should order 129.54 meters of steal.

Step-by-step explanation:

I just went on google and typed in "ft. to meters converter".

7 0

3 years ago

Please help me ill put the question up for a lot of point, and i will mark as brainliest!!!

sattari [20]

Step-by-step explanation:

(2x³y^-4)^-2 = 1/(4x⁶y^‐8) = y⁸/(4x⁶)

1/(8x⁵y^-7) = y⁷/(8x⁵)

4x^-9y⁴ = 4y⁴/x⁹

so, the whole expression is then

y⁸/(4x⁶) × y⁷/(8x⁵) × 4y⁴/x⁹

4y¹⁹/(32x²⁰) = y¹⁹/(8x²⁰)

so, D is the correct answer.

6 0

2 years ago

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

tigry1 [53]

Answer:

$P(A) = \frac{30}{100}$

$P(B) = \frac{77}{100}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

$Yes = 22$ and $No = 8$

So, we have:

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

So, we have:

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

8 0

3 years ago

Can the sides of a triangle have lengths 2, 7, and 8?

Natalka [10]

Answer:

Yes

Step-by-step explanation:

As long as any two numbers added are greater than the number not chosen they can make a triangle

2+7= 9 9 is greater than 8

8+2= 10 10 is greater than 7

7+8= 15 . 15 is greater than 2

3 0

3 years ago

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pashok25 [27]

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3 years ago