The order does not matter, so we will be using combinations here. 52C1 is the first one since there is only one possibility. 16C1 is the second. You have to multiply these two, so 52 X 16 = 832.
I think it would be most likely A the first one.
Answer:
I would guess 40, I could be wrong.
Step-by-step explanation:
70-30=40. So it would be 40 units away from eachother.
He would have 21 before he bought the 10 stamp because 31-10=21
Answer:
n<50
Step-by-step explanation:
7/2*5n + 14<49
7n/2*5+14<49
(7n)+(2*5)14/2*5 <49
7n+10*14/2*5 <49
7n+140/2*5 <49
7n+140/10 <49
7n+140 < 10*49
7n+140 < 490
(7n+140)+(-140)<490+(-140)
7n+140-140<490-140
7n<350
7n/7 < 350/7
n<2*5^2*7/7
n<2*5^2
n<2*25
n<50
