<span>mostly collect like terms
use associative property which is
(a+b)+c=a+(b+c)
also -a+b-c=(-a)+(b)+(-c) so you can move them around
and remember that:
you just use a general rule
x+x=2x
x^2+x^2=2x^2
3xy4xy=7xy
3x+4x^2=3x+4x^2
you
can only add like terms( like terms are terms that are same name like x
or y are differnt, and like terms have same power exg x^2 and x^3 and
x^1/2 and such
I will oly put the naswers because I don't have much time
first one: 2a+3b+2c
second one: remember that -(-6c)=+6c so the answer is c-10a-2b
third one: -a-8b-5c
</span>
Answer:
false
Step-by-step explanation:
Answer:
Is this a go ogle meet
Step-by-step explanation:
I don’t have time now :(
Answer:
Step-by-step explanation:
Gym A has a $150 joining fee and costs $35 per month.
Assuming that Casey wants to attend for x months, the cost of using gym A will be
150 + 35 times x months. It becomes
150 + 35x
Gym B has no joining fee and costs $60 per month.
Again, assuming that Casey wants to attend for x months, the cost of using gym B will be
60 × x months = 60x
A) To determine the number of months that it will both gym memberships to be the same, we will equate them.
150 + 35x = 60x
60x - 35x = 150
25x = 150
x = 150/25 = 6
It will take 6 months for both gym memberships to be the same.
B) If Casey plans to only go to the gym for 5 months,
Plan A will cost 150 + 35×5 = $325
Plan B will cost 60 × 5 = $300
Plan B will be cheaper
Answer:
Step-by-step explanation:
Complete Question:
Chapter 6, Section 1-D, Exercise 009 Is a Normal Distribution Appropriate? In each case below, is the sample size large enough so that the sample proportions follow a normal distribution?
a) n=600 p=0.2
b) n=20, p=0.4
if np=10 and npq=10 then the data follows normal distribution
a) np= 120,
q= 1-0.2= 0.8
npq= 600 ×0.2×0.4 = 48
Normal distribution is appropriate and sample size is large enough
b) np= 8
q= 1-0.4= 0.6
npq= 20 × 0.4×0.6= 4.8
sample size is not large enough so normal distribution is not appropriate.
