What is the unit rate of 1.94 foor 4 pounds of bananas?

Mathematics

1 answer:

jekas [21]3 years ago

5 0

1.94 / 4 = 0.485 rounds to 0.49 per lb

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the formula y-y=m(x-x) is the point -slope from of the equation of a line where m is the slope of the line and (x,y) and ( x,y)

hodyreva [135]

(4,-2)(5,0)
slope(m) = (0 - (-2) / (5 - 4) = 2/1 = 2
there is going to be 2 possible answers...

y - y1 = m(x - x1)
now we sub

using points (4,-2)..... y -(-2) = 2(x - 4) =
y + 2 = 2(x - 4) <==

using points (5,0)....y - 0 = 2(x - 5) <==

8 0

3 years ago

Chicken Delight claims that 90% of its orders are delivered within 10 minutes of the time the order is placed. A sample of 90 or

kkurt [141]

<h2>Answer with explanation:</h2><h2></h2>

Let p be the population proportion of orders are delivered within 10 minutes of the time the order is placed.

Then according to the claim we have ,

$H_0:p=0.90\\\\ H_a:p\neq0.90$

Since the alternative hypothesis is two-tailed so the hypothesis test is a two-tailed test.

For sample ,

n = 90

Proportion of orders are delivered within 10 minutes of the time the order is placed= $\hat{p}=\dfrac{80}{90}\approx0.89$

Test statistics for population proportion :-

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\=\dfrac{0.89-0.90}{\sqrt{\dfrac{0.90(0.10)}{90}}}\approx-0.32$

The p-value : $2(z>-0.32)=0.7489683\approx0.75$ [By using standard normal distribution table]

Since the p-value is greater that the significance level (0.01), so we do not reject the null hypothesis.

Hence, we conclude that we have enough evidence to support the claim that 90% of its orders are delivered within 10 minutes of the time the order is placed.

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3 years ago

If m< LMP is 11 degrees more than m< NMP and m< NML =137, find each measure

Agata [3.3K]

First, note that for angles LMP and NMP you have

$m\angle LMP+m\angle NMP=m\angle NML.$