Answer:
BC ≈ 8.6
Step-by-step explanation:
Using Pythagoras' identity in the right triangle , that is
BC² = AB² + AC² = 7.3² + 4.6² = 53.29 + 21.16 = 74.45 ( square root both sides )
BC = 
≈ 8.6 ( to 1 dec. place )
Answer:
1,171,875
Step-by-step explanation:
The sequence is multiplying by 5 every time. It will be 3, 15, 75, 375, 1875, 9375, 46,875, 234,375, and then 1,171,875
complete question:
The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?
Answer:
The original number is 10a + b = 10 × 3 + 5 = 35
Step-by-step explanation:
Let
the number = ab
a occupies the tens place while b occupies the unit place. Therefore,
10a + b
The sum of the digits of two-digits numeral
a + b = 8..........(i)
If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.
Therefore,
10b + a = 18 + 10a + b
10b - b + a - 10a = 18
9b - 9a = 18
divide both sides by 9
b - a = 2...............(ii)
a + b = 8..........(i)
b - a = 2...............(ii)
b = 2 + a from equation (ii)
Insert the value of b in equation (i)
a + (2 + a) = 8
2a + 2 = 8
2a = 6
a = 6/2
a = 3
Insert the value of a in equation(ii)
b - 3 = 2
b = 2 + 3
b = 5
The original number is 10a + b = 10 × 3 + 5 = 35
Answer:
D. x<2
Step-by-step explanation:
-1+ 6-1-3x) >- 39 - 2x
Multiply the parentheses by 6
- 1-6 - 18x > - 39 - 2x
Calculate
7- 18x > - 39 - 2x
Move the terms
18x + 2x > -39 +7
Collect like terms Calculate
- 16x>-32
Divide both sides by - 16
x < 2
Answer:
Let x = # of commercials
y = # of movies
<u>System of Equations:</u>
x + y = 90
40x + 110y = 500
Step-by-step explanation:
We have to set our variables before we start solving. After setting the variables, we can set up the equations. If x = # of commercials and y = # of movies, then we can assume x + y = 90, as there have been a total of 90 commercials and movies played altogether. Then, we know that their worth is $500, so the price of all the commercials played and the price of all the movies played (which is 40x + 110y) sum to $500.
