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2 years ago

35. Luke and Matthew ran a lemonade

1 answer:

6 0

70% 30 = 21 I highly recommended using google it’s so much easier then this app sometimes because you won’t have to answer other people’s questions hahaha I’m only using it bc I can’t find the answers on google for my homework

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What are the real and complex solutions of the polynomial equation X^3-216=0

vazorg [7]

Answer:

$6,\ -3+3\sqrt{3}i,\ -3-3\sqrt{3}i$

Step-by-step explanation:

Factor the equation $x^3-216=0$ using formula for difference of the cubes:

$x^3-216=(x-6)(x^2+6x+36),$

then

$x-6=0\ or\ x^2+6x+36=0.$

1. The equation $x-6=0$ has real solution $x=6.$

2. The equation $x^2+6x+36=0$ has negative discriminant $D=6^2-4\cdot 36=36-144=-108,$ then it has two complex solutions

$x_{1,2}=\dfrac{-6\pm 6\sqrt{3}i}{2}=-3\pm3\sqrt{3}i.$

3 0

3 years ago

Decide whether the data in the table represent a linear function or an

liq [111]

Answer:-8

Step-by-step explanation:

6 0

3 years ago

What is the solution to the equation 9r=4/7

Vera_Pavlovna [14]

Answer:

r=4/63

Step-by-step explanation:

Divide each term in 9r=47 by 9 and simplify.

8 0

1 year ago

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Ayudaaa necesito resolver 2 ejercicios <br> A) √x+2=x <br> B) 3+√2x-6=x

mojhsa [17]

Answer:

A) x=4

B)x= $\sqrt{2}$ +3 or 7.24

Step-by-step explanation:

5 0

2 years ago

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Is it ever possible that sin (A+B)= sin⁡ A+sin⁡ B? If so, explain how. If not, explain why not.

Contact [7]

The formula for the sine sum is

$\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b)$

So, equation

$\sin(a)\cos(b)+\cos(a)\sin(b) = \sin(a)+\sin(b)$

Cannot be solved with standard ways. However, we can build special cases to make it work.

The most trivial example would be A=B=0. In this case, we have

$\sin(0+0)=0 \sin(0) = 0,\quad\sin(0)+\sin(0)=0+0=0$

If we work on this idea a little bit, we can produce examples like

$A=2k_1\pi,\quad B=2k_2\pi$

And again we have

$\sin(A+B)=\sin(2\pi(k_1+k_2))=0$

$\sin(A)+\sin(B)=\sin(2k_1\pi)+\sin(2k_2\pi)=0+0=0$

So, yes, it is possible that $\sin(A+B)=\sin(A)+\sin(B)$ , although solving the equation directly would be quite difficult.

5 0

3 years ago

Read 2 more answers