Assuming that you're talking about a standard deck of 52 cards, there are 4 tens and 4 aces.
So, at the beginning, you have probability 4/52=1/13 to draw a ten.
You replace, and you have an identical probability to draw an ace (you still have 4 favourable cases over 52 total cases).
Multiply the two probabilities to find the answer:
Answer:
They are vertical angles
x = 5
The mesure of the angles are 35, 35, 145, and 145
Step-by-step explanation:
vertical angles are derectly acrost from each other.
the equations 3x+20 and 10x-15, put into the equation 3x+20=10x-15 will solve for x.
20 = 10x − 15 − 3x
20 = 7x - 15
20 + 15 = 7x
35 = 7x
35/7 = x
5 = x
x = 5
The equations solved are 3 x 5 + 20 = 35 and 10 x 5 - 15 = 35
The sum of all the angles is 360, therefore 35 + 35 = 70
360 - 70 = 290
290/2 = 145
The last two angles are 145 degrees
The algebraic representation of the expression ten minus one-third of number is 4 is 10 - 1/3x = 4
<h3>Algebra</h3>
ten minus one-third of number is 4
let
10 - 1/3x = 4
10 - 4 = 1/3x
6 = 1/3x
x = 6 ÷ 1/3
x = 6 × 3/1
x = 18
Therefore, the algebraic representation of the expression ten minus one-third of number is 4 is 10 - 1/3x = 4
Learn more about algebra:
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Sequence: 1,7,49,343,??,16807, 7th term, 8th....
we notice that:
1st term = 1 or 7^0
2nd term = 7 or 7^1
3rd term =49 or 7^2
4th term = 343 or 7^3
5th term = ?? or 7^4 (=2401)
6th term = 16807 or 7^5
7th term = 117 647 or 7^6
nth term = (7)^(n-1)
