Question

The product of two consecutive even integers is 728.What are the integers?

Answer 1

$2n\cdot(2n+2)=728\\ 4n^2+4n-728=0\\ n^2+n-182=0\\ n^2+14n-13n-182=0\\ n(n+14)-13(n+14)=0\\ (n-13)(n+14)=0\\ n=13 \vee n=-14\\\\ 2n=26 \vee 2n=-28\\ 2n+2=28 \vee 2n+2=-26$

26 nad -28 or -26 and 28