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3 years ago

Find a value for b so that the polynomial x^2+ bx + 25 factors to (x + 5)^2.

Mathematics

1 answer:

Marta_Voda [28]3 years ago

7 0

Answer:

10 = b

Step-by-step explanation:

Begin by expanding (x + 5)^2

(x + 5)(x + 5)

First: x*x = x^2

Outside: x * 5 (the last term which is a 5)

Inside: 5+ x

Last: 5*5 = 25

x^2 + 5x + 5x + 25

x^3 + 10x + 25

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Table of values for y=2x^2-2x

Pachacha [2.7K]

Answer:

$x= -2, -1, 0, 1, 2\\y= 12, 4,0,0,4$

Step-by-step explanation:

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2 years ago

Is it C or no? Can u help please

Westkost [7]

the answer is Probably C.

7 0

3 years ago

I need help with solving it

mars1129 [50]

The given equation has a slope of $\frac{-9}{7}$ . Parallel lines have the same slope.

Point-Slope formula: y - y₁ = m(x - x₁) ; where (x₁, y₁) is the point and "m" is slope

y - y₁ = m(x - x₁)

y - (-4) = $\frac{-9}{7}$ (x - 2)

y + 4 = $\frac{-9}{7}$ x + $\frac{18}{7}$

- 4 - $\frac{28}{7}$

y = $\frac{-9}{7}$ x - $\frac{10}{7}$

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3 years ago

What is the slope of x+y=7,x-y=8

slava [35]

Step-by-step explanation:

The slop is M= 1÷x-y-xy

5 0

3 years ago

What is the interquartile range of the data set

Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

Other method:

You don't need this step.

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: The number of values + 1 / 2

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

Other method:

For an odd number of values: The number of values + 1 / 4

11 + 1 / 4 = 12 / 4 = 3

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Using the values greater than the median, exclusive, find the median:

For an odd number of values: The number of values + 1 / 2

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

Other method:

For an odd number of values: (The number of values + 1 / 4) * 3

(11 + 1 / 4) * 3 = (12 / 4) * 3 = 3 * 3 = 9

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Your interquartile range is 3 - 25

25 - 3 = 21

8 0

3 years ago