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Rina8888 [55]
3 years ago
15

34 down, 16 left to go!

Mathematics
1 answer:
Kazeer [188]3 years ago
6 0
I would say that B. is the right answer.
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I need help i couldnt understand this!!
Black_prince [1.1K]
For #1 you have to make the denominator the same so it will be 4 and 8/16 and 5 and 9/16 Then subtract them. For #3 you divide 175 by 7.
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3 years ago
If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r
Jobisdone [24]
The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number. 

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58
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3 years ago
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blagie [28]

Answer:

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Step-by-step explanation:

The x and y do not match up

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if set up like

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it would be 4 and 6

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