These two lines are parallel
You can use desmos
Answer:
Step-by-step explanation:
F(x) = x² - 2x + 1
= (x - 1)²
By comparing this equation with the vertex form of the quadratic equation,
y = (x - h)² + k
Here, (h, k) is the vertex
Vertex of the parabola → (1, 0)
x-intercepts → (x - 1)² = 0
x = 1
y-intercepts → y = (0 - 1)²
y = 1
Now we can draw the graph of the given function,
From this graph,
As x → 0,


f(0) = (0 - 1)²
= 1
Since, 
Therefore, given function is continuous at x = 0.
Answer:
-8 < x < inf
[-8 , inf )
Step-by-step explanation:
set up a +/- |x + 8| = x + 8
the setup a number line and use test points
Example C: w cubed z, +, 5, z squared, minus z squared, +, 6 ..... For example, 2x + 1 = 7x and 10x minus 9y minus z = 3 are linear equations, but x, +, y ...
Step-by-step explanation:
Area of triangle = 1/2 . base . height