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3 years ago

HELPPPPPPPPPPPP PLEASE

Mathematics

1 answer:

Gennadij [26K]3 years ago

6 0

Answer: <B is congruent to <E

Step-by-step explanation:

There is no “angle,angle,angle” theorem when proving triangles are congruent.

There are 5 however that do:

ASA (angle, included side, angle)

SSS (side, side, side)

SAS (side, included angle, side)

AAS (angle,angle, non included side)

HL (hypotenuse,leg)

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The area of a square is64. Cm <br><br> What is the length of its side

zhuklara [117]

Answer:

The length is 8 cm. Since its a square, so the length of both its sides are equal.

l^2=64

where l=length of side

square root both sides

then, l=8

4 0

3 years ago

Read 2 more answers

A man buys 3 chicken sandwiches at 2.75 each and 2 cokes at 1.19 and the tax is $0.64. he gives you 11.52. how much change shoul

Artist 52 [7]

3 chicken sandwiches at $2.75 each: 3*2.75= 8.25

2 cokes at 1.19: 2*1.19= 2.38

Tax: 0.64

8.25+2.38+0.64= 11.27

He gives you 11.52, to find how much you need to give him back, subtract how much he gives you by the amount that is charged (11.27)

11.52-11.27= $0.25

3 0

3 years ago

Find quotient 10/6 / 1/ 24

Maru [420]

Answer:

Step-by-step explanation:

Quotient means dividing so we must divide 10/6 by 1/24.

10/6 ÷ 1/24

10/6 * 24/1 = 40 <--- Multiply by the reciprocal in order to divide.

Final Answer: 40

I hope this helps! :)

3 0

2 years ago

Nicholas put 1,012 baseball cards into boxes. He put 22 cards in each box. How many boxes did Nicholas need for these baseball c

valentina_108 [34]

Answer:

46 boxes

Step-by-step explanation:

1012 / 22 = 46

3 0

2 years ago

I can't figure out how to do (i + j) x (i x j)for vector calc

Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

$\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}$

Then, solving the determinant

$\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}$

In our case,

$\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}$

Where we used the formula for AxB to calculate ixj.

Finally,

$\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}$

Thus, (i+j)x(ixj)=i-j

8 0

1 year ago