(3/2)x-1<2x+4
3x-2<4x+8
-2<x+8
-10<x
x>-10
3((2/3)x + 1) < 11
(3*2/3)x+1*3<11
2x +3<11
2x<8
x<4
so the compound equality is the set of all numbers which are >-10 or <4, which are D) all real numbers
What you would do is convert the sizes to equal each other
|-3| is an absolute value. This means it will always be positive. -3 is an integer and is negative.
The GCF will be found as follows:
-27x^2yz^5+15x^3z^3
-27x^2yz^5=-3*3*3*x*x*y*z*z*z*z*z
15x^3z^3=3*5*x*x*x*z*z*z
the GCF is the product of the lowest power of each factor that appears in each term
thus we shall have:
3*z*z*z*x*x
=3z^3x^2
