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3 years ago

Explain how to solve 3b=48. Give the solution in you explanation

Mathematics

2 answers:

AveGali [126]3 years ago

8 0

Answer:

1) Divide both sides by 3

2) b=16

Step-by-step explanation:

To solve the equation, we want to find out what b is. In order to do this, we have to get b by itself. Perform the opposite of what is being done to the equation. Keep in mind, everything done to one side, has to be done to the other.

3b=48

3 and b are being multiplied (3b=3*b). The opposite of multiplication is division. Therefore, divide both sides by 3.

3b/3=48/3

The 3s on the left will cancel, and we are left with:

b=48/3

b=16

givi [52]3 years ago

5 0

Answer:

b=16

Step-by-step explanation:

1) Divide 3 on both sides.

2) 3 divided by 3 and 48 divided 3.

3) Now you're left with 16, so the value of b is 16.

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Devaughn's age is three times Sydney's age. The sum of their ages is . What is Sydney's age?

g100num [7]

Answer:

syd is 23 and dev is 69

Step-by-step explanation:

Let Dev's age be x and Syd's age be y

Since Dev is 3 times older than Syd, we may write

Since the sum of their ages is 92, we may write

Now replacing x with 3y, we get :

Hence

and so Syd is 23 year old.

Back substituting we get Dev is 69 years old.

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3 years ago

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Oksi-84 [34.3K]

Would the common factor be 1?
edit
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3 years ago

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MatroZZZ [7]

Answer:

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Step-by-step explanation:

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3 years ago

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9966 [12]

Answer:

its always wrong

Step-by-step explanation:

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3 years ago

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Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. (a) Descr

Daniel [21]

Answer:

(a) The sampling distribution of $\overline{X}$ = Population mean = 79

(b) P ( $\overline{X}$ greater than 81.2 ) = 0.1357

(c) P ( $\overline{X}$ less than or equals 74.4 ) = .0107

(d) P (77.6 less than $\overline{X}$ less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean $(\nu)$ = 79

Standard deviation $(\sigma )$ = 18

(a) Describe the sampling distribution of $\overline{X}$

For large sample using central limit theorem

the sampling distribution of $\overline{X}$ = Population mean = 79

(b) What is Upper P ( $\overline{X}$ greater than 81.2 ) =

$P(\overline{X}> 81.2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})$

= $P(Z> 1.1)$

= $1 - P(Z< 1.1)$

= 1 - .8643 =

= 0.1357

$P(\overline{X}\leq 74.4)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{74.4- 79}{\frac{18}{\sqrt{81}}})$

= $P(Z\leq -2.3)$

= .0107

(d) What is Upper P (77.6 less than $\overline{X}$ less than 83.2 ) =

$P(77.6< \overline{X}< 83.2)$ = $P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{83.2- 79}{\frac{18}{\sqrt{81}}})$

= $P(- 0.7< Z< 2.1)$

= $(Z< 2.1) - (Z< -0.7)$

= 0.9821 - .2420

= 0.7401

3 0

3 years ago