Solve using equations:
Gina 11 = a+b+c
Sam 27 = 2a+3b+2c
Robby 19= a+2b+2c
Gina *2 give 22=2a+2b+2c (subtract this from Sam to give)
b=5
the subtract Robby from Gina *2 to give a=3
[Question 1]
let d = number of dramas Gina rented, c = # of comedies, and t = # of documentaries:
[equation a] d + c + t = 11
[equation b] 2d + 3c + 2t = 27
[equation c] d + 2c + 2t = 19
if we subtract [a] from [c] we get:
[equation d] c + t = 8
if we subtract [c]*2 from [b] we get:
[equation e] -c - 2t = -11 or
[equation e] c + 2t = 11
Now we can subtract [e] from [d] to solve for t:
t = 3
Now put in 3 for t in [d] or [e] to solve for c:
c + 2(3) = 11
c + 6 = 11
c = 5
So she rented 5 comedies and 3 documentaries which leaves 3 dramas (which is answer A)
This is the concept of algebra, To solve the question we proceed as follows;
Number of chocolate cake left=23
The number of pieces that was left after the cake was divided into 2 equal pieces will be:
23*2
=46
Number of strawberry cake left = 56
The number of pieces that was left after the cake was divided into 3 equal pieces will be:
56*3
=168
Comparing the two fraction, the flavor that had larger pieces was strawberry cake;
This cake was larger compared to chocolate by:
168-46
=122
The answer is Strawberry by 122 of a cake
Answer: x = 9, y = 5
Step-by-step explanation:
If all of the sides are equal, it is an equilateral triangle. Equilateral triangles are also equiangular. The angles of a triangle add up to 180 degrees, so each angle must equal 60 degrees.
set the equation equal to 60 to solve for x
7x - 3 = 60
add three to both sides
7x = 63
divide both sides by 7
x = 9
find y by setting the equation equal to 60
11y + 5 = 60
subtract 5 from each side
11y = 55
divide both sides by 11
y = 5
Common denominator is going to be 24
8=2*2*2
6=2*3
24=2*2*2*3
8 should be multiplied by 3
6 should be multiplied by 4
7/8=(7*3)/(8*3)=21/24
5/6=(5*4)/(6*4)=20/24
7/8=21/24
5/6=20/24
Answer:
D.
Step-by-step explanation:
A.
9 (x - 3) = 9x - 27 ➡ 0 = 0 (this has infinite solutions)
B.
9x - 3 = 9x - 3 ➡ 0 = 0 (has infinite solutions)
C.
9x - 3 = 27x - 3 ➡ x = 0 (has one solution)
D.
9 (x + 3) = 9(x + 10) ➡9x +27 = 9x +90➡ 9x -9x = 90 - 27 ➡ 0 = 63 (doesn't make sense so it has no solution)
