Name the mathematical property for an equation

What is the length. is the triangle similar .

forsale [732]

Answer:

The triangle are similar and the missing line is 16.5

Step-by-step explanation:

The reason is because the scale factor is 2. You can find this out by multiply 8×2=16 and 9×2=18. With this in mind you divided 11 by 2 to get 5.5 for LD. Finally, adding 11+5.5 you will get 16.5.

Hope this helped

5 0

3 years ago

Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,

Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁, of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

$Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times (720-576)\times (720 - 672)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times 144 \times 48}$ = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

$Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}$

The semi-perimeter, s₂, of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

$Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times (690 -228)\times (690 - 480)}$

$Area\, of \, \Delta ACD = \sqrt{690 \times 18\times 462\times 210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2$

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0

3 years ago

The RANGE of this function is A) [1, 5] B) [3, ∞) C) [-4, ∞) D) (-∞, ∞)

velikii [3]

y = (x - 1)(x - 5) -> polinom

Range = (-∞, ∞) (D)

5 0

4 years ago

Read 2 more answers

Help look at my photo

STALIN [3.7K]

Answer:

A x² +2x +4
D x² +10x +26

Step-by-step explanation:

One way to determine if the equation has any real solutions is to look at its discriminant. For the equation ax²+bx+c = 0, the discriminant is ...

d = b² -4ac

When the discriminant is negative, both solutions to the quadratic are complex. There are no real solutions in that case.

We can find the discriminant values to be ...

A: d = 2² -4(1)(4) = -12 . . . . no real zeros

B: d = 0² -4(3)(-5) = 60 . . . two real zeros

C: d = 8² -4(-2)(0) = 64 . . . two real zeros

D: d = 10² -4(1)(26) = -4 . . .no real zeros

Expressions A and D have no real zeros.

_____

Comment on the question

You are given an expression, not an equation. There is no equal sign. Hence, we cannot talk about solutions. We can only talk about zeros, values of x that make the expression have a value of zero.

5 0

3 years ago

Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).

Lapatulllka [165]

Hello!

The formula for the area of a sector can be written as follows:

Area = $\frac{1}{2}$ $r^{2}$ (R)

In the above formula, “r” represents the radius while “R” represents the radian measure of a sector. The radius is given to us in the image above as 10 inches. However, we still need the radian measure of the two sectors. To find this measure, we can use the following conversion:

1 degree = $\frac{pi}{180}$ radians

Because the two sectors have a given measure of 72 degrees, we need to multiply both sides of the above conversion by 72:

72 degrees = $\frac{72pi}{180}$

Reduce the fraction on the right side of the equation:

72 degrees = $\frac{2pi}{5}$

We now have the radian measure of both sectors. Now simply insert this and any other known values into the “area of a sector” formula above:

Area = $\frac{1}{2}$ $10^{2}$ ( $\frac{2pi}{5}$ )

Simplify the right side of the equation to get the following answer:

Area = 20 pi

We have now proven that the area of one sector is equal to 20 pi.

If, however, you need the combined area of the two identical sectors, simply multiply the proven area by 2 to get a total area of 40 pi.

I hope this helps!

3 0

3 years ago