D=a=-3? was that written correctly?
Answer:
Step-by-step explanation:
Slope: 1
y - intercept: (0,4)
Let (x,y) be an arbitrary point on the circle.
Then d = √[x-3)2 + (y-0)2] = √[x2 - 6x + 9 + y2]
Since x2 + y2 = 1, y2 = 1-x2.
So, d = √[x2 - 6x + 9 + 1 - x2]
d = √(-6x+10)
Domain: x is the x-coordinate of a point on the circle centered at (0,0) with radius 1. So, -1≤x≤1.
But, for d to be defined, we need -6x+10 ≥ 0. So, x ≤ 5/3 (True for all x in [-1,1]).
Domain = [-1,1]
Range: -1 ≤ x ≤ 1 So, 6 ≥ -6x ≥ -6
16 ≥ -6x+10 ≥ 4
4 ≥ √(-6x+10) ≥ 2 That is, 2 ≤ d ≤4
Range: [2,4]
Step-by-step explanation:
He will weigh 198 lbs. you add 3 lbs to his original weight for each year.
Answer:
a)30-1,2,3,5,6,10,15,30
b)20-1,2,4,5,10,20
Step-by-step explanation:
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