Answer:
x = 2x
x + 20 = 2x + 20
And,
1.5(x + 20) = 2x + 20
x = 20 i.e. Alexis
And, Jelani be 40
Step-by-step explanation:
Given that
Jelani has twice as much as Alexis
And, both can added $20
Jelani will have 1.5 times as much on his pass on Alexis
We need to write an equation also the amount does Jelani and Alexis have
So,
Let us assume the alexis be x
And, Jelani be 2x
Now
x = 2x
x + 20 = 2x + 20
And,
1.5(x + 20) = 2x + 20
1.5x + 30 = 2x + 20
-0.5x = -10
x = 20 i.e. Alexis
And, Jelani be 40
N^2 because 2n is the same as n+n, but n^2 is the same as the product of n and n
Answer:
4*x^4*y^22
Step-by-step explanation:
Your goal here is to REDUCE the given expression to simplest terms.
One way in which to approach this problem would be to rewrite (2x^2y^10)^3 as: (2x^2*y^8)*y^2*(2x^2*y^10)^2.
Dividing this rewritten expression by 2x^2*y^8 results in:
y^2(2x^2*y^10)^2.
We now need to raise (2x^2*y^10) to the power 2. Doing this, we get:
4x^4*y^20.
Multiply this by y^2 (see above):
y^2*4x^4*y^20
The first factor is 4: 4y^2*x^4*y^20. This is followed by the product of y^2 and y^20: 4*y^22*x^4
Finally, this should be re-written as
4*x^4*y^22
Another way of doing this problem would involve expanding the numerator fully and then cancelling out like factors:
8*x^6*y^30 4*x^4*y^22
----------------- = ------------------ = 4*x^4*y^22
2x^2y^8 1
Answer:
3.5 
Step-by-step explanation:
If the shape is half of a circle, you will be using this formula: A = 
π 
Your radius is half of the diameter. r = d/2 = 3/2 = 1.5
Substitute r = 1.5 into the formula.
A = π 
A = (3.14)
Use your calculator to find the answer and round your answer.
3.5
Answer:
8 / sqrt(3)
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp / adj
tan A = BC / AC
tan 30 = BC / 8
8 tan 30 = BC
8 * sqrt(3)/3 = BC
8/3 sqrt(3) = BC
