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Kruka [31]
3 years ago
7

When you are given two angle measures and the length of the included side, do you get a unique triangle

Mathematics
1 answer:
Alenkasestr [34]3 years ago
8 0
Yes ...you get a unique triangle.

You might be interested in
Can someone help me I really need it
Dennis_Churaev [7]

Answer:

The 3 lines are parallel.

Step-by-step explanation:

To draw the lines with the slope of 1/3 choose any point and mark it, then go up 1 square and right 3 squares and mark that point. Draw a line connecting those 2 points. Now choose another point and do the same thing. Then once more. Lines with the same slope are parallel.

Hope this helped! Please mark Brainliest.

8 0
3 years ago
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
What algebraic expression must be added to the sum of 3x2 +4x+8 and 2x2−6x+3 to give 9x2−2x−5 as the result?
vesna_86 [32]

Answer:

4x^2-16

Step-by-step explanation:

-This is an addition/subtraction problem.

#We subtract the sum of the first two expression from the third expression:

\#Add \ first \ two\\\\=3x^2 +4x+8 +2x^2-6x+3\\\\=5x^2-2x+11\\\\\# Subtract\ from \ the \ third\\=(9x^2-2x-5)-(5x^2-2x+11)\\\\=9x^2-2x-5-5x^2+2x-11\\\\=4x^2-16

Hence, the expression 4x^2-16 must be added to the first two.

7 0
3 years ago
Please need help on this
artcher [175]

Answer:

the center is (-4,7) and the radius is 3

Step-by-step explanation:

The center of a circle can be found using the equation (x-h)^2 + (y-k)^2 = r^2 and is (h,k) from it. Notice h and k are the opposite value as in the equation.  

First write the equation in this form.  

x^2 + 8x + ( ?)+ y^2 - 14y + (?) + 56 = 0  

Complete the square with each variable to find what numbers should go in place of the question marks.  

(8/2)^2 = 4^2 = 16  

(-14/2)^2 = -7^2 = 49  

Add 16 and 49 to both sides of the equation.  

x^2 + 8x + 16 + y^2 - 14y + 49 + 56 = 16 + 49\\(x+4)^2 + (y-7)^2 + 56 = 65\\(x+4)^2 + (y-7)^2 = 9  

So the center is (-4,7) and the radius is 3.

5 0
3 years ago
A real estate agent has 14 properties that she shows. She feels that there is a 50% chance of selling any one property during a
Ratling [72]

Answer:

91.02% probability of selling more than 4 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The chance of selling any one property is independent of selling another property. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.5

Compute the probability of selling more than 4 properties in one week.

Either you sell 4 or less properties in one week, or you sell more. The sum of the probabilities of these events is decimal 1. So

P(X \leq 4)  + P(X > 4) = 1

We want to find P(X > 4). So

P(X > 4) = 1 - P(X \leq 4)

In which

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.5)^{0}.(0.5)^{14} = 0.000061

P(X = 1) = C_{14,1}.(0.5)^{1}.(0.5)^{13} = 0.000854

P(X = 2) = C_{14,2}.(0.5)^{2}.(0.5)^{12} = 0.0056

P(X = 3) = C_{14,3}.(0.5)^{3}.(0.5)^{11} = 0.0222

P(X = 4) = C_{14,4}.(0.5)^{4}.(0.5)^{10} = 0.0611

So

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000061 + 0.000854 + 0.0056 + 0.0222 + 0.0611 = 0.0898

Finally

P(X > 4) = 1 - P(X \leq 4) = 1 - 0.0898 = 0.9102

91.02% probability of selling more than 4 properties in one week.

8 0
3 years ago
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