6< 2g - 4. With process
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with that template in mind, let's see
the period of 2π, well, for that, you have to do nothing, because that's sine original period
Amplitude of 1, well, that's also sine's original amplitude
horizontal shift/phase... ok, that means C/B = π, now, it doesn't say if to the left or the right, so I gather either is ok, so...let's do the right
you could use then, C = -π and B = 1, that gives you -π/1 or -π
vertical shift of -4, well, that simply means D = -4
f(θ) = sin(θ - π) - 4 <-- will do