3 years ago

about 47% of the 15152 samples researchers found were bacteria. what percent of the samples were not bacteria?

Mathematics

1 answer:

timofeeve [1]3 years ago

3 0

47% of them were bacteria, which means 53% of them were not bacteria.

47+53=100 or 100-47=53

I hope this helps :)

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Given:

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Required

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The above can be written as

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$-0.36 * a^{2+1+2} *b^{1+2+3} *x^{5+1}$

$-0.36 * a^{5} *b^{6} *x^{6}$

$-0.36 a^{5}b^{6} x^{6}$

Hence, $a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3$ is equivalent to $-0.36 a^{5}b^{6} x^{6}$

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