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PtichkaEL [24]
3 years ago
14

A u B u C A=(a,b,c,d,e) B=(d,e,f,g,h,i) C=(a,e,i,o,u) help class 8​

Mathematics
2 answers:
cupoosta [38]3 years ago
4 0

Answer:

<h3>if;</h3>

A= { a,b,c,d,e}

B= {d,e,f,g,h,i}

C= {a,e,i,o,u}

AuBuC = {a,b,c,d,e,f,g,h,i,o,u}

HAVE A NİCE DAY

Step-by-step explanation:

GREETİNGS FROM TURKEY ¯ツ

BlackZzzverrR [31]3 years ago
3 0

Answer:

If U = { a, b, c, d, e, f, g, h} , find the complements of the following sets:(i) A = {a, b, c} (ii) B = {d, e, f, g} (iii) C = {a, c, e, g} (iv) D = { f, g, h, a}

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Step-by-step explanation:

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3 years ago
Write an exponential equation in the form y = abx whose graph passes through points (4, 8) and (6, 32).
Artist 52 [7]

Answer:

Option C.

Step-by-step explanation:

The general exponential equation is

y=ab^x

It is given that the graph of exponential function passes through points (4,8) and (6,32). It means the equation of exponential function must be satisfied by these points.

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32=ab^6       ...(2)

Divide equation (2) by equation (1).

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Taking square root on both sides.

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3 years ago
Many people use scanners to read documents and store them into pdf file. To help determine which brand of scanner to buy, a stud
konstantin123 [22]

The data is missing in the question. The data is provided below :

Document : 1     2      3      4      5     6      7      8

Brand A       17  29    18    14    21   25    22    29

Brand B       21  38    15    19    22   30    31   37

Solution :

State of the hypothesis of the null hypothesis and alternate hypothesis.

Null hypothesis : $h_A = h_B$

Alternate hypothesis : $h_A > h_B$

These hypothesis is a one tailed test. The null hypothesis will get rejected when the mean difference between the sample means is very small.

Significance level = 0.05

Therefore the standard error is :  $SE = \sqrt{(\frac{s^2_1}{n_1})+(\frac{s^2_2}{n_2})}$

                                                         = 3.602

And the degree of freedom, DF = 14

$t=\frac{(x_1-x_2)-d}{SE}$

 = -1.319

Here, $s_1$ = standard deviation of the sample 1

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         $n_1$ = size of the sample 1

        $n_2$ = size of the sample 2

         $x_1$ = mean of the sample 1

        $x_2$ = mean of the sample 2      

          d = the hypothesis difference between the population mean

The observed difference in a sample means t static of -1.32. From t distribution calculator to determine P($t \leq -1.32$) = 0.1042  

Since the P value of 0.1042 is greater than significance level o 0.05, we therefore cannot reject the null hypothesis.

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8 0
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