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Nina [5.8K]
3 years ago
8

5. Tanya made a deposit of $150 into her

Mathematics
2 answers:
wariber [46]3 years ago
8 0

Answer:

$300

Step-by-step explanation:

Tanya started with 350 dollars

She deposited $150

150 + 350 = 500

Then she withdrew (took out) $55

500 - 55 = 445

Then she wrote a check for $145, this means she gave someone a check so the money is going to be taken out of her account.

445 - 145 = 300

So Tanya has $300 in her account

xenn [34]3 years ago
5 0
She now has $300 in her account
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PLEASE HELP
mihalych1998 [28]

Answer: The height is 4.472

Step-by-step explanation: That formula is Heron's formula.

Where "s" is calculated like this:

s = (a + b + c) / 2

In this case:

a = 14

b = 12

c = 6

replacing:

s = (14 + 12 + 6) / 2

s = 16

Now we calculate the area:

A ^ 2 = 16 * (16−14) * (16−12) * (16−6)

A ^ 2 = 1280

A = 35.777

The area of the triangle is:

A = b * h / 2

In this case we will take the base as the longest side of the triangle, that is to say = 14

Thus:

h = A * 2 / b

h = 35.777 * 2/16

h = 4.472

So the height is 4.472

8 0
2 years ago
Darius flipped a coin 500 times and it landed heads up 300 times .What is the relative frequency of the coin landing heads up ba
Leto [7]

To find the relative frequency, we have to first divide 300 by 500 and on doing so we will get 0.6 .

And then to find the percentage, we need to multiply it with 100 . And 0.6 times 100 = 60%.

So out of the given 4 options, correct option is the last option .

7 0
3 years ago
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0.13391963118/17(3.78)
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Answer:

Simplify the expression.

0.02977742

Step-by-step explanation:

i think i hope its right

7 0
2 years ago
Twenty-five samples of 100 items each were inspected when a process was considered to be operating satisfactorily. In the 25 sam
notsponge [240]

a) The estimate of the proportion of defectives when the process is in control is 0.054

b) The standard error of the proportion if the sample size is 100 is 0.0226.

c) The upper control limit is 0.1218 and the lower control limit is 0 (since LCL < 0 and p > 0, we can write LCL = 0).

<h3>What are the formulas for finding the estimate of the proportion, standard variation, and control limits?</h3>

1) The estimate of the proportion of success is

p = (number of success)/(total number of samples)

I.e., p = x/N

2) The standard deviation of the proportion of success is

\sigma_p = \sqrt{\frac{p(1-p)}{n} }

3) The upper and lower control limits for a control chart are:

L.C.L = p - 3\sigma_p

and U.C.L = p + 3\sigma_p

<h3>Calculation:</h3>

It is given that, there are 25 samples of 100 items each.

So, the total number of items i.e., the total sample size,

N = 25 × 100 = 2500

In 25 samples, a total of 135 items were found to be defective.

So, the number of defectives x = 135

a) The estimate of the proportion of defectives is p = x/N

On substituting, we get

p = 135/2500 = 0.054

b) The standard error of the proportion if the sample of size 100 is calculated by

\sigma_p = \sqrt{\frac{p(1-p)}{n} }

On substituting p = 0.054 and  n = 100, we get

\sigma_p = \sqrt{\frac{0.054(1-0.54)}{100} }

    = 0.0226

c) The control limits for the control chart are:

Upper control limit =  p + 3\sigma_p

⇒ U.C.L = 0.054 + 3(0.0226) = 0.054 + 0.0678 = 0.1218

Lower control limit = p - 3\sigma_p

⇒ L.C.L = 0.054 - 3(0.0226) = 0.054 - 0.0678 = - 0.0138 ≈ 0

(Since we know that the lower control limit should not be a negative value, it is made equal to 0).

Learn more about an estimate of the proportion here:

brainly.com/question/23986522

#SPJ4

7 0
1 year ago
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