Heyy can you please help me posted picture of question
2 answers:
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Correct Question is: Find the illegal values of b in the fraction (2b^2 + 3b - 10)/(b^2 - 2b - 8)
illegal values are those which are not a part of Domain. In this case these will be such values which will make the denominator of the fraction zero.
So setting the denominator equal to zero, we can find these values.
Thus, b=-2 and b=4 are the illegal values for this expression
illegal values are those which are not a part of Domain. In this case these will be such values which will make the denominator of the fraction zero.
So setting the denominator equal to zero, we can find these values.
Thus, b=-2 and b=4 are the illegal values for this expression
the complete question is
<span>Point A has an x coordinate of −2 and lies in a circle with a center at (0, 0) and a radius of 5.
To the nearest tenth, what is the y-coordinate for point A?
A: 4.5
B: 4.6
C: 4.7
D: 4.8
see the attached figure
we know that
the equation of the circle is
(x-h)</span>²+(y-k)²=r²
(h,k) is the center---------> (h,k) is the point (0,0)
r=5 units
so
(x-h)²+(y-k)²=r²--------> (x-0)²+(y-0)²=5²------> x²+y²=25
substitute the value of x=-2 in the equation
(-2)²+y²=25------> y²=25-4------> y=(+/-)√21
the y coordinate of point A is positive----> see the picture
therefore
y=√21-----> 4.58-----> y=4.6
the answer is
the y-coordinate for point A is 4.6
<span>Point A has an x coordinate of −2 and lies in a circle with a center at (0, 0) and a radius of 5.
To the nearest tenth, what is the y-coordinate for point A?
A: 4.5
B: 4.6
C: 4.7
D: 4.8
see the attached figure
we know that
the equation of the circle is
(x-h)</span>²+(y-k)²=r²
(h,k) is the center---------> (h,k) is the point (0,0)
r=5 units
so
(x-h)²+(y-k)²=r²--------> (x-0)²+(y-0)²=5²------> x²+y²=25
substitute the value of x=-2 in the equation
(-2)²+y²=25------> y²=25-4------> y=(+/-)√21
the y coordinate of point A is positive----> see the picture
therefore
y=√21-----> 4.58-----> y=4.6
the answer is
the y-coordinate for point A is 4.6