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3 years ago

Help with maths question please

Mathematics

1 answer:

mars1129 [50]3 years ago

6 0

<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Substitute -3 into g(x)

g(-3) = 2(-3) + 4

Solve:

g(x) = -2

Substitute this value into f(x)

f(-2) = 3(-2)^2

Solve:

f(-2) = 12

The answer is B. 12

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Find the area of the shaded region to the nearest tenth. See picture for full problem. Please and thank you so much!

Anestetic [448]

Answer:

Step-by-step explanation:

Radius =6 ft

Area of circle = πr²

= 3.14 * 6 * 6

= 113.04 ft²

base = 10.39 ft

height = 6+3 = 9 ft

$Area \ of \ triangle = \dfrac{1}{2}*base * height\\\\\\=\dfrac{1}{2}*10.39*9\\$

= 46.76 ft²

Area of the shaded region = area of circle - area of triangle

= 113.04 - 46.76

= 66.28

= 66.3 ft²

8 0

2 years ago

I need help on these questions

Advocard [28]

For #4, we know V = lwh
We have the values
5184 = 2(18)h
Solve for h
5184 = 36h
144 = h.

for # 3:
we know A = pi r^2
We have
A = 3.14 * 6^2
A = 3.14 * 36
A = 113.04

for #2:
We know C = 2pi *r
C = 2(3.14)(14)
C = 28(3.14)
C = 87.92

for #1:
C = 2pi * r
C = 2(3.14)(26.3/2)
C = 2(3.14)(13.15)
C = 26.3(3.14)
C = 82.582

4 0

3 years ago

I NEED HELPPP WITH THISSS

goblinko [34]

Answer:

$\boxed{\boxed{\sf (-20) }}$

given - X = (-8).

Y = 7
Z = (-11)

To find - Value of this equation

Solution-

(-13) -Y

putting the value of y = 7 in the equation

(-13) -7

-20

3 0

2 years ago

Read 2 more answers

solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+

Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

$\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.$

Write the augmented matrix for the system of equations

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)$

Find the reduced row-echelon form of the augmented matrix for the system of equations:

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)$