2 years ago

6% of a length is 390m what is the original length

Mathematics

1 answer:

LenaWriter [7]2 years ago

7 0

6500

Explanation:

Picture

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alekssr [168]

Answer:

3384

Step-by-step explanation:

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3 years ago

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Ivahew [28]

C. 12 /3 go Brainly! Have Fun

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3 years ago

2m·4b−3a·2n−0.2b·5m+n·5a−5bm+8an

cupoosta [38]

Answer:

2bm + 7an

Step-by-step explanation:

Multiply.

8bm - 6an - bm + 5an - 5bm + 8an

Combined like terms:

8bm - 6an - bm + 5an - 5bm + 8an

= 2bm + 7an

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3 years ago

4x+23=9x-38 21y-1 value of y

PSYCHO15rus [73]

Answer:

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2 years ago

6. a semicircle has as its diameter the hypotenuse of a right triangle shown below. determine the area of the semicircle to the

jeyben [28]

Answer:

$A = 137.3cm^2$

Step-by-step explanation:

Given

See attachment

Required

The area of the semicircle

First, we calculate the hypotenuse (h) of the triangle

Considering only the triangle, we have:

$\cos(68) = \frac{7}{h}$ --- cosine formula

Make h the subject

$h = \frac{7}{\cos(68)}$

$h = \frac{7}{0.3746}$

$h = 18.7$

The area of the semicircle is then calculated as:

$A = \frac{\pi h^2}{8}$

This gives:

$A = \frac{3.14 * 18.7^2}{8}$

$A = \frac{1098.03}{8}$

$A = 137.3cm^2$

7 0

3 years ago