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Mice21 [21]
3 years ago
11

I WILL AWARD BRAINLIEST!! PLEASE HELP!!

Mathematics
1 answer:
MrRa [10]3 years ago
6 0

Answer:

1) By SAS theorem, ΔADE≅ΔCDF

2) By SSS theorem, ΔBDE≅ΔBDF

Step-by-step explanation:

Consider isosceles triangle ABC (see diagram).

1. In triangles ADE and CDF:

AD≅DC (since BD is median, then it divides side AC in two congruent parts);

AE≅CF (given);

∠A≅∠C (triangle ABC is isosceles, then angles adjacent to the base are congruent).

By SAS theorem, ΔADE≅ΔCDF.

2. In triangles BDE and BDF:

side BD is common;

DE≅DF (ΔADE≅ΔCDF, then congruent triangles have congruent corresponding sides);

BE≅FB (triangle ABC is isosceles, AB≅BC, AE≅CF, then BE=AB-AE, FB=BC-CF).

Be SSS theorem, ΔBDE≅ΔBDF.

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Beatrice built about 1/3 of a sandcastle. Linda built 4/7 of the same castle. What fraction of the sandcastle did they build tog
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Answer    

Find out the what fraction of the sandcastle did they build together .

To prove

Let us assume that the fraction of the sandcastle  they build together be x .

As given

Beatrice\ built\ about\ \frac{1}{3}\ of\ a\ sandcastle.

Linda\ built\ \frac{4}{7}\ of\ the\ same\ castle.

Than the equation becomes

x = \frac{1}{3} +\frac{4}{7}

L.C .M of (3,7) = 21

solving

x = \frac{7 + 3\times4}{21}

x = \frac{19}{21}

Therefore the fraction of the sandcastle did they build together be

x = \frac{19}{21}

Hence proved



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