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Arada [10]
3 years ago
14

Using sine and cosine, explain how you know where the graph of tangent will

Mathematics
1 answer:
notsponge [240]3 years ago
4 0

Remember how the tangent function is defined as

\frac{sinx}{cosx}

Now where exactly are the vertical assymptotes? Well, where cosx = 0, because  anything over 0 is undefined, and where a value is undefined, you are required to draw  a vertical assymptote.  

Now where exactly are the x interecepts? Well, where sinx = 0, because remember, an x-intercept  is where y = 0, or where it crosses the x-axis, meaning where the tangent function is equal to 0.

So the x-intercepts are at where sinx = 0.

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The bar graph shows how each month's rainfall compares to the historical average.
mina [271]

Answer:

a. The difference in rainfall is 4.03in

b. The total amount of rainfall for the year is negative, -1.73

Step-by-step explanation:

a. Wettest month 2.36in and dryest month -1.67in

2.36

-1.67

-------

4.03

b. -0.45   +   -0.88   +   0.94   +   -1.67   +   -0.96   +   0.83   +   2.36   +   1.39   +   0.35   +   -1.35   +   -0.9   +   -1.39 = -1.73

3 0
3 years ago
For g (2) = 3x – 2 find the value of x<br> -<br> for which g(x) = 10
hram777 [196]

Answer:

For g (2) = 3x -2 find the value of x

The value of x is 2

for which g(x) = 10?

10 = 3x -2

10 +2 = 3x

12 = 3x

x = 12/3

x = 4

3 0
3 years ago
How do you do distributive property because I have a test tomorrow and it's like half my grade and I wasn't in school when they
BaLLatris [955]
Say you have the equation 5(5x+7)=155
First you multiply 5 by everything in the parenthesis so you get 25x+35=155 then subtract 35 from both sides and get 25x=120 then 120 divided by 25 equals 4.8 so x=4.8
4 0
3 years ago
Courtney has a total of 88 stamps worth $15.56. Some are $0.25 stamps and some are $0.02 stamps. How many of each foes she have?
olganol [36]

Let x = # of 25-cent stamps

y = # of 2-cent stamps

{   x+ y = 88

{ 0.25x + 0.02y = 15.56

60 25-cent stamps 28 2-cent stamps

5 0
3 years ago
On your wedding day you leave for the church 34 minutes before the ceremony is to begin, which should be plenty of time since th
Schach [20]

Answer:

Average speed   is 37.35 mi/h

Step-by-step explanation:

given data

leave =  34 minutes before

church distance =  12.0 miles

average speed first 17 minutes =  5.0 mi/h

solution

so we find Total distance travel in first 17 minutes = speed × time

Total distance travel in first 17 minutes = 5 × \frac{17}{60}

Total distance travel in first 17 minutes = 1.416 mi

and

Distance Remaining = 12 - 1.416 = 10.584 mi

Time Remaining = 34 - 17 min = 17 min

so

remaining distance Average speed  = \frac{distance}{time}

Average speed  = \frac{10.584}{\frac{17}{60}}

Average speed   is 37.35 mi/h

3 0
3 years ago
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