Answer:
-5 5/8
Step-by-step explanation:
Answer:
all rectangles are quadrilaterals
Step-by-step explanation:
this is because they have all right angles it doesn't matter the size or measurements, and this goes for squares as well since squares are a type of rectangle and we all know that squares have all equal side lengths and they all have right angles
Answer:
B
Step-by-step explanation:
Given y and x vary directly then the equation relating them is
y = kx ← k is the constant of variation
To find k use the condition y = 27 when x = 4 , then
27 = 4k ( divide both sides by 4 )
= 6.75 = k
y = 6.75x ← equation of variation
When x = 12 , then
y = 6.75 × 12 = 81
The answer is A I don’t this before
Answer:
b)
![x^{2} +\frac{b}{a} x+(\frac{b}{2 a} )^{2} = \frac{-c}{a} + (\frac{b}{2 a}) ^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%5Cfrac%7Bb%7D%7Ba%7D%20x%2B%28%5Cfrac%7Bb%7D%7B2%20a%7D%20%29%5E%7B2%7D%20%3D%20%5Cfrac%7B-c%7D%7Ba%7D%20%2B%20%28%5Cfrac%7Bb%7D%7B2%20a%7D%29%20%5E%7B2%7D)
Step-by-step explanation:
<u>Step(i)</u>:-
Given quadratic equation ax² + bx + c = 0
<u>step(ii)</u>:-
ax² + bx = -c
<u>Step(iii):</u>-
Dividing 'a' on both sides , we get
![\frac{ax^{2} +bx }{a} = \frac{-c}{a}](https://tex.z-dn.net/?f=%5Cfrac%7Bax%5E%7B2%7D%20%2Bbx%20%7D%7Ba%7D%20%3D%20%5Cfrac%7B-c%7D%7Ba%7D)
![x^{2} + \frac{bx}{a} = \frac{-c}{a}](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%20%5Cfrac%7Bbx%7D%7Ba%7D%20%20%3D%20%5Cfrac%7B-c%7D%7Ba%7D)
<u><em>Step(iv)</em></u>:-
Adding
on both sides , we get
![x^{2} +\frac{b}{a} x+(\frac{b}{2 a} )^{2} = \frac{-c}{a} + (\frac{b}{2 a}) ^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%5Cfrac%7Bb%7D%7Ba%7D%20x%2B%28%5Cfrac%7Bb%7D%7B2%20a%7D%20%29%5E%7B2%7D%20%3D%20%5Cfrac%7B-c%7D%7Ba%7D%20%2B%20%28%5Cfrac%7Bb%7D%7B2%20a%7D%29%20%5E%7B2%7D)