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3 years ago

Which set of values are equivalent. ,

Mathematics

1 answer:

Gnoma [55]3 years ago

3 0

3/10, 30%, 0.3

because 3/10 basically means 3 out of 10. that's 30%. 0.3 is just 3/10 in decimal form.

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Find the distance between the two given points. O(-3,-2) and P(-3,4)

aliina [53]

Answer:

$\boxed {\boxed {\sf d= 6}}$

Step-by-step explanation:

Distance can be found using this formula:

$d=\sqrt {(x_2-x_1)^2+(y_2-y_1)^2$

Where (x₁, y₁) and (x₂, y₂) are the points.

We are given the points O (-3, -2) and P(-3,4). Therefore,

$x_1= -3 \\y_1= -2 \\x_2= -3 \\y_2=4$

Substitute the values into the formula.

$d=\sqrt {(-3--3)^2+(4--2)^2$

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition and Subtraction.

Solve inside the parentheses first.

(-3--3)= -3+3=0
(4--2)= 4+2=6

$d= \sqrt {(0)^2+ (6)^2}$

Solve the exponents.

(0)²= 0*0=0
(6)²= 6*6=36

$d=\sqrt {0+36$

Add.

$d= \sqrt {36$

Take the square root.

$d=6$

The distance is 6.

3 0

3 years ago

Find the value of x round to the nearest tenth

Usimov [2.4K]

Answer:the answer is FREE COINS!

Step-by-step explanation:

5 0

3 years ago

Divide.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

yulyashka [42]

It's not clear whether the problem is to:

(1) divide $x^2-4$ by $\dfrac{x-8}{x-2}$ , or

(2) divide $\dfrac{x^2-4}{x-8}$ by $x-2$ .

But with only two possible cases, that's not much work to do.

$\drac{x^2-4}{\frac{x-8}{x-2}}=\dfrac{(x^2-4)(x-2)}{x-8}=\dfrac{x^3-2x^2-4x+8}{x-8}$

Synthetic division yields a quotient and remainder of $x^2+6x+44+\dfrac{360}{x-8}$ (see attachment for how the algorithm was carried out).

In the other case,

$\dfrac{\frac{x^2-4}{x-2}}{x-8}=\dfrac{\frac{(x-2)(x+2)}{x-2}}{x-8}=\dfrac{x+2}{x-8}$

provided that $x\neq2$ . Synthetic division can be used again here, but this is quite easy to deal with by just doing some easy manipulation of the numerator:

$\dfrac{x+2}{x-8}=\dfrac{x-8+10}{x-8}=\dfrac{x-8}{x-8}+\dfrac{10}{x-8}=1+\dfrac{10}{x-8}$

(also provided that $x\neq 8$ )