Amplitude:4
Equation of Midline: 2
Period of function:3
Function shifted left:0.5
Function shifted up: 2
We have
3 / (x-5) - x/5
We make the GCF and we have
15/[ 5(x-5) ] - x(x-5)/[ 5(x-5)]
= [ 15 - x(x-5) ] [5(x-5)]
= [ 15 - x^2 + 5x] / [ 5 (x-5) ]
= [15 - x^2 + 5x]/[5x - 25]
An answer to your question is (15-x^2+5x)/(5x-25)
97yards...............................................................................................................................................................................................................................................................................................................
I believe it would be (b) (-2,1)
55/9 = 6.11
57/7 = 8.14
41/5 = 8.2
65/8 = 8.125
The answer is 41/5 is larger than 8.15
