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3 years ago

Which is harder linear algebra or abstract algebra?

2 answers:

6 0

They both relatively easy depending on how much time you put into understanding but. But if I have to pick which is harder I’d say linear.

Leokris [45]3 years ago

5 0

Linear algebra

I've always had trouble with graphs and it's much better if the algebra is similar to arthemetic

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Write an expression in simplest form for the perimeter of each figure

Juli2301 [7.4K]

QUESTION 12

The given figure has five unequal sides.

The perimeter is the distance around the figure.

So we add all the lengths of the sides of the rectangle to get,

$Perimeter = 5x + 4x + 2.8y + 2x + 2.2y$

We regroup the like terms to obtain,

$Perimeter = 5x + 4x +2x + 2.8y + 2.2y$

This will simplify to give us,

$Perimeter = 11x + 5.0y$

$Perimeter = 11x + 5y$

QUESTION 13

The given figure has two pairs of sides that are equal in length and three unequal sides.

The perimeter can be found by adding all the lengths of the sides of the of the figure.

This will give us

$Perimeter = 6b + 5a + 3b + 4 + 3a + 2b + 5a$

We regroup like terms to obtain,

$Perimeter = 6b + 2b+ + 3b + 5a + 5a +3a + 4 +$

This finally simplifies to ,

.
$Perimeter = 11b + 13a + 4 +$

QUESTION 14

This plane figure has four sides that are equal to 4j and two sides that are equal to 2h.

We add all the lengths of the sides of the plane figure to get,

$Perimeter =4j + 4j+ 4j+ 4j + 2h + 2h$

This will simplify to give us,

$Perimeter =16j + 4h$

6 0

3 years ago

Three water storage containers have the same volume in the shape of a cylinder, a cone, and a sphere. The base radius of the cyl

fredd [130]

Answer:

- The ratio of the height of the cone to the height of the cylinder is 3:1

- The ratio of the height of the cone to radius of the sphere is 4:1

Step-by-step explanation:

Note that the radii of all the structures are the same.

Let the height of the cone be H and the height of the cylinder be h

The volume of each of the shapes are given below as

Volume of cylinder = πr²h

Volume of a cone = (1/3)πr²H

Volume of a sphere = (4/3)πr³

1) The ratio of the height of the cone to the height of the cylinder

To obtain this, we equate the volume of those two structures

Volume of the cone = Volume of the cylinder

(1/3)πr²H = πr²h

πr² cancels out on both sides and we're left with

(H/3) = h

H = 3h

(H/h) = (3/1)

So, The ratio of the height of the cone to the height of the cylinder is 3:1

2) The ratio of the height of the cone to radius of the sphere

Similarly equating the volumes of the cone and the sphere

(1/3)πr²H = (4/3)πr³

(1/3)πr² cancels out on both sides and we're left with

H = 4r

(H/r) = (4/1)

The ratio of the height of the cone to radius of the sphere is 4:1

Hope this Helps!!!

8 0

3 years ago

The function f(x) is given by the set of ordered pairs. {(1,0), (–10,2), (0,6), (3,17), (–2,–1)} Which equation is true? f of ne

Rudik [331]

Answer:

f(0)=6

Step-by-step explanation:

When representing function's values by set of ordered pairs, the first one correspond to the x value and the second to the image or "y" value.

When you read f(0) means "when x is 0" then the 6 is the value of the function or the image.

7 0

3 years ago

Read 2 more answers

PLEASE HELP ME, ill give points! Im in the 7th grade

sdas [7]

Answer: y=-5 x=5

explanation: look at the number the x and y is on

4 0

2 years ago

If m1=40 find the measure of <3

Reika [66]

Not clear your question !

6 0

3 years ago