Which is harder linear algebra or abstract algebra?
2 answers:
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y = 1/3x
The slope is 1/3 ( the slope is the number with the variable x).
There is no other operation ( addition or subtraction) so the y- intercept is 0
The first point of the graph would be (0,0)
Calculate another point , lets use x = 3
y = 1/3(3) = 1
The second point is (3,1)
The line of the graph is an angled line which is located in quadrant 1 and 3.
See attached picture:
The answer is , because i searched it up
