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Verdich [7]
4 years ago
14

Which equation can be used to find the measure of angle LJK?

Mathematics
1 answer:
Colt1911 [192]4 years ago
3 0
Is there a picture that comes with the problem?
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baker has 5\dfrac145 4 1 ​ 5, start fraction, 1, divided by, 4, end fraction pies in her shop. She cut the pies in pieces that a
kupik [55]

Answer:

The answer is "She cut a total of 42 pieces of pie".

Step-by-step explanation:

Given :

Total pie=  5 \frac{1}{4}

cut pie = \frac{1}{8}

The number of pieces of the pie she has=?

Solve the mixed fraction value:

\to 5 \frac{1}{4}= \frac{21}{4}

If she cuts the pieces into the entire pie, that is  = \frac{1}{8}  

So, the equation is:

\to \frac{21}{4} = \frac{1}{8} \times x

\to x= \frac{21 \times 8}{4}\\\\ \to x= 21 \times 2\\\\ \to  x=42

7 0
3 years ago
A measurement that measures distance and it's basic unit is meter
Elena L [17]

Answer:

the correct answer is option A. Length

7 0
3 years ago
-24n^4+90n^2-50 / 2n^2-5
horrorfan [7]
<span> -28n4 + 65n2 - 5 hope this helps</span><span> </span>

4 0
4 years ago
Complete the recursive formula of the geometric sequence 27, -9, 3, -1... b(1) = b(n) = b(n - 1)⋅
valina [46]

Answer:

- 1/3

Step-by-step explanation:

When you multiply -1/3 with 9 you get 3! and so on

6 0
3 years ago
The firm is requested to send 3 employees who have positive indications of asbestos on to a medical center for further testing.
Rus_ich [418]

Answer:

0.0645 = 6.45% probability that exactly 10 employees will be tested in order to find 3 positives

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

40% of the employees have positive indications of asbestos in their lungs

This means that p = 0.4

a) Find the probability that exactly 10 employees will be tested in order to find 3 positives

2 within the first 9(P(X = 2) when n = 9), and the 10th, with 0.4 probability. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{9,2}.(0.4)^{2}.(0.6)^{7} = 0.1612

0.4*0.1612 = 0.0645

0.0645 = 6.45% probability that exactly 10 employees will be tested in order to find 3 positives

4 0
3 years ago
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