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melamori03 [73]
2 years ago
13

Help please !! I have school in an hour

Mathematics
1 answer:
Roman55 [17]2 years ago
6 0

Answer:

0.25

Step-by-step explanation:

the unit rate in this case is the cost per line, you decide 2.00 by 8

2.00/8=0.25

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Does anyone know how to do this? please help me
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On the x column, you would write 1, 2, 3, 4, and so on. Then, in the y box, you plug in that number into the equation. Write your answer in the y column. 

For example, if x = 1, then 1^2 + 2 - 8 = - 5. 
If x = 1, y= -5
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Identifiy the mode of the followinng numbers:2,5,6,6,11,19,20
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remember that a mode is a number repeated in the data set ( or the number list.

Mode: 6

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2 years ago
Help me please thank you so much if you did
Gala2k [10]

Answer:

I just answed this question today!Your asnwer is 144.

Step-by-step explanation:

1:5:3

48 total.

Divide 48 and get 16

<u>Multiply 16 x1</u>

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The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room
Alexandra [31]

Answer:

\bar x = 260.1615

\sigma = 70.69

The confidence interval of standard deviation is: 53.76 to 103.25

Step-by-step explanation:

Given

n =20

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}

\bar x = \frac{5203.23}{20}

\bar x = 260.1615

\bar x = 260.16

Solving (b): The standard deviation

This is calculated as:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}

\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}\sigma = \sqrt{\frac{94938.80}{19}}

\sigma = \sqrt{4996.78}

\sigma = 70.69 --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

c =0.95

So:

\alpha = 1 -c

\alpha = 1 -0.95

\alpha = 0.05

Calculate the degree of freedom (df)

df = n -1

df = 20 -1

df = 19

Determine the critical value at row df = 19 and columns \frac{\alpha}{2} and 1 -\frac{\alpha}{2}

So, we have:

X^2_{0.025} = 32.852 ---- at \frac{\alpha}{2}

X^2_{0.975} = 8.907 --- at 1 -\frac{\alpha}{2}

So, the confidence interval of the standard deviation is:

\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} } to \sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }

70.69 * \sqrt{\frac{20 - 1}{32.852} to 70.69 * \sqrt{\frac{20 - 1}{8.907}

70.69 * \sqrt{\frac{19}{32.852} to 70.69 * \sqrt{\frac{19}{8.907}

53.76 to 103.25

8 0
2 years ago
Sara got fast food for lunch. She paid $1.12 on soup and $5.47 on a hotdog with a $20 bill. What was the change from the purchas
leonid [27]

Answer: 13.41$


Step-by-step explanation:


6 0
3 years ago
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