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3 years ago

Find the value of the logarithm. log 210 Round your answer to the nearest thousandth.

Mathematics

2 answers:

Hunter-Best [27]3 years ago

7 0

Answer:

Your correct answer is 5.347

Dmitry_Shevchenko [17]3 years ago

3 0

Answer:

5.347

Step-by-step explanation:

5.3471075307175.

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You got paid $343 for 7 hours of work. Find the unit rate.

pshichka [43]

Answer:

$49 / hour

Step-by-step explanation:

343/7 = $49/hour

7 0

3 years ago

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A certain restaurant sells coffee for 2.00 and donuts for 1.50. If the restaurant sold 80 items and earned 141.50 how many donut

Korvikt [17]

Answer:

$280

Step-by-step explanation:

if you do 2.00+1.50 you get 3.50. Then you do 3.50 ×80 you get 280 dollars

6 0

4 years ago

1. If Jose says that 75% of his class of 28 students

kondaur [170]

C. 21 kids ride the bus

5 0

3 years ago

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Whats the answers please

Rzqust [24]

Answer:

Since the ray bd is bisecting the angle abc, equate 3x + 4 to 7x - 20.

Step-by-step explanation:

3x + 4 = 7x - 20

x = 6

.. Therefore, angle abc = 3x + 4 + 7x - 20

= 18 + 4 + 42 - 20

= 44

4 0

3 years ago

Among a group of 100 people, 68 can speak English, 45 can speak French, 42 can speak Spanish. 27 can speak both English and Fren

Nat2105 [25]

Answer:

Step-by-step explanation:

Given

No of People who can speak English is $n(E)=68$

No of People who can speak French is $n(F)=45$

No of People who can speak Spanish is $n(S)=42$

No of People who can speak both English and French $n\left ( E\cap F\right )=27$

No of People who can speak both English and Spanish $n\left ( E\cap S\right )=25$

No of People who can speak both French and Spanish $n\left ( F\cap S\right )=16$

No of people who can speak all languages is $n\left ( E\cap F\cap S\right )=9$

no of People who can Speak at least one Language is

$n\left ( E\cup F\cup S\right )=n\left ( E\right )+n\left ( F\right )+n\left ( S\right )-n\left ( E\cap F\right )-n\left ( E\cap S\right )-n\left ( F\cap S\right )+n\left ( E\cap F\cap S\right )$

$n\left ( E\cup F\cup S\right )=68+45+42-27-25-16+9=96$

Probability that Randomly selected can speak at least 1 of these languages

$P=\frac{96}{100}=0.96$

8 0

3 years ago