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ki77a [65]
3 years ago
8

Which of these relations are functions?

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
4 0
It’s the first one, so you’re correct
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Solve the quadratic equation by completing the square.<br> QUESTION ATTCHED BELOW!!!!!!!!!!
Mariulka [41]

Answer:

x ≈ - 9.41, x ≈ - 6.59

Step-by-step explanation:

Given

x² + 16x + 62 = 0 ( subtract 62 from both sides )

x² + 16x = - 62

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(8)x + 64 = - 62 + 64

(x + 8)² = 2 ( take the square root of both sides )

x + 8 = ± \sqrt{2} ( subtract 8 from both sides )

x = - 8 ± \sqrt{2}

Hence

x = - 8 - \sqrt{2} ≈ - 9.41

x = - 8 + \sqrt{2} ≈ - 6.59

4 0
3 years ago
Read 2 more answers
Resolve to me these exercises please?
Dima020 [189]
A)4^(n+3)=8^14
2^(2×(n+3))=2^(3×14)
2^(2n+6)=2^42
2^2n=2^36
n=18

b) (assuming a : is divide)
3^(2n+1)=9^17/3^3
3^(2n+1)=3^(2×16)/3^3
3^(2n+1)=3^29
3^2n=3^28
2n=28
n=14

d) (6^n)^4×36=216^10
6^4n×6^2=6^(3×10)
6^(4n+2)=6^30
6^4n=6^28
4n=28
n=7

e)7^(n^2)÷7=49^24
7^(n^2-1)=7^(2×24)
7^(n^2)=7^49
n^2=49
n=7

g)15^(n+4)÷5^(n+4)=81^6
3^(n+4)×5^(n+4)÷5^(n+4)=3^(4×6)
3^(n+4)=3^24
n=20

h)81^n÷9^n+9^(n+2)÷9=90÷9^6
9^2n÷9^n+9^(n+2)÷9=9*10/9^6
9^n+9^(n+1)=10/9^5
I don't know where to go from here

I)what?
7 0
3 years ago
Y(x) = e^x+rx+sx^2 satisfies y'' − y' = 5x if r=? and s=?
motikmotik

Answer:

5

Step-by-step explanation:

3 0
3 years ago
Round 0.0645 g to 2 significant figures: ___ g<br> 0.064 <br> 0.06 <br> 0.065 <br> 0.1
Anna11 [10]
0.065 as 0 doesn't count as a significant number
6 0
3 years ago
Read 2 more answers
Solve for x<br> decreasing 3/4 times a number by 18 is equal to increasing 1/2 times the number by 5
Eva8 [605]

Step-by-step explanation:

let the no. be x then

3/4x-18=1/2x+5

3/4x-1/2x=18+5

1/4x=23

x=23×4

x=92

4 0
3 years ago
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