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1 year ago

Solve for y.

Mathematics

2 answers:

posledela1 year ago

6 0

Answer:

y <−2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

pickupchik [31]1 year ago

6 0

Answer:

y<2

Step-by-step explanation:

12-6y>24

-12. _12

-6y>24

_y<2

y<-2

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Find the next term of the following sequence.<br><br> 25, 10, 4,

arlik [135]

The given sequence is 25, 10, 4.

Notice that this is a geometric sequence because here we have equal common ratio.

So, common ratio : r = $\frac{a_{2}}{a_{1}}$

= $\frac{10}{25}$

= 0.4

So, each term is 0.4 times of it's previous term.

Hence, to get the next term of this sequence, multiply 0.4 with the third term 4.

So, fourth / next term = 4* 0.4 =1.6

Hence, next term of this sequence is 1.6.

Hope this helps you!

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2 years ago

Antwone earns money at a steady rate mowing lawns. The points (1,25) and (5,125) appear on a graph of the amount earned versus n

Volgvan

Use rise over run to find slope. If you don't know what that is, its y2-y1/x2-x1. Y2 is 125, Y1 is 25, X2 is 5, and X1 is 1. You then plug the numbers in, 125-25=100. 5-1=4. then you divide 100/4, in which you get 25. So you times 25 by 3, getting 75.

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2 years ago

A motorcycle can travel 70 miles per gallon. Approximately how many gallons of fuel will the motorcycle need to travel 60 km?

Likurg_2 [28]

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2 years ago

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The probability that a professional baseball player will get a hit is 1/3. Calculate the exact probability that he will get at l

Evgesh-ka [11]

It is given here that there is 1/3 probability of professional baseball player will get a hit. Hence if at least three hits are gained out of 5 attempts, the calculation goes: 5C3* (1/3)^3*(2/3)^2 + 5C4* (1/3)^4*(2/3)^1 +5C5 *<span>(1/3)^5*(2/3)^0 equal to 0.21. </span>

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3 years ago

A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.

oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

$H_0: \mu=2.4\\\\H_a:\mu> 2.4$

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58$

The degrees of freedom for this sample size are:

$df=n-1=45-1=44$

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.5801)=0.0066$

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

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2 years ago