The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
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A. 2 hours and 25 minutes
Answer:
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Step-by-step explanation:
For all real numbers a,b, and c, the distributive property states that:
For Part A, we have
Or
For Part B, we have
-4(3x-10)+5(2-6x)=-4*3x--4*10+5*2-5*6x
This simplifies to:
-4(3x-10)+5(2-6x)=-12x+40+10-30x
-4(3x-10)+5(2-6x)=-12x-30x+40+10
-4(3x-10)+5(2-6x)=-42x+50
For the C part, we have:
For Part D, we have:
We simplify to get:
Simplify further to get:
5 and 2/3 because 51/9= 5.666666667, which .66666667 in fraction form is 2/3
We can turn this word problem into the following equation:
x^2 + 85 = (x - 17)^2
x^2 + 85 = x^2 - 34x + 289
-85 -85
_______________________
x^2 = x^2 - 34x + 204
+34x +34x
_______________________
x^2 + 34x = x^2 + 204
-x^2 -x^2
____________________
34x = 204
Divide 34 on both sides
x = 6.
The number is 6.
