Question

I need to find the zeros of the function, please

Answer 1

Move the -2x^2 over to the other side to make it positive and then rewrite in descending order of x's. Like this: 2x^2 - 12X + 18. Factor out a 2 to make things easier: 2(x^2 - 6x + 9). Now factor what's inside the parenthesis. Both signs are the same and they're both negative: (x - )(x -  ). It's up to us now to find out what goes inside there with those x's. What adds up to -6 has to multiply to +9. Two 3's fit inside there perfectly: -3-3=-6, and -3*-3=9, so the factors are (x-3)(x-3), and setting those equal to zero according to the Zero Product Property, x-3=0 so x = 3 with a multiplicity of 2.