Answer:
Amy worked for 128 hours while Brayden worked for 112 hours
Step-by-step explanation:
Given
Let A represents Amy and B represents Brayden
A = 16 + B ------(1)
A:B = 8:7------- (2)
Required
Find A and B;
Convert (2) to fractions
Cross Multiply
Substitute A = 16 + B in the above expression
Open Bracket
Subtract 7B from both sides
Recall that A = 16 + B
Hence,
<em>This implies that Amy worked for 128 hours while Brayden worked for 112 hours</em>
The probability that the total number of heads in all the coin tosses equals 12 is 0.0273.
Given a fair dice and tossing a fair coin sixteen times.
We have to find the probability that the total number of heads in all the coin tosses equals 12.
The probability lies between 0 and 1.
Probabiltiy of coming head when the coin is tossed 1 time is 0.5 and probability of coming tails is also 0.5.
Let X shows the sum of heads while tossing.
P(X=12)=?
We can find the probability using binomial theorem.
=
We have to toss sixteen times and out of 16 times we need head 12 times.
=16!/12!4!*0.00024*0.0625
=1820*0.000015
=0.0273
Hence the probability that the total number of heads in all the coin tosses equals 12 is 0.0273.
Learn more about probability at brainly.com/question/24756209
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Answer:
Solve: x < 3 Graph: *attached* Interval Notation: (-∞,3)
Step-by-step explanation:
Solve:
combine like terms
Add 6 on either side of the inequality
Divide by 6 on either side of the inequality
Graph:
*see attachment*
Interval notation:
(-∞ , 3)
